From: Phillip Wood <phillip.wood123@gmail.com>
To: Ondra Medek <xmedeko@gmail.com>, git@vger.kernel.org
Subject: Re: Checkout to different directory at certain commit without changing index
Date: Mon, 13 May 2024 16:28:44 +0100 [thread overview]
Message-ID: <13fa579b-8987-4430-967c-42b9de8acb6d@gmail.com> (raw)
In-Reply-To: <CAJsoDaEJn1Y0CgtxpkGqVRsTiDnMxjNFrtbTuUVOvT87N23JNg@mail.gmail.com>
Hi Ondra
On 13/05/2024 08:26, Ondra Medek wrote:
> Hello,
> I need a simple script for unskilled users to do a fast checkout (LFS
> friendly) of the current local Git clone at a certain commit to a
> different directory I.e. something like "copy at a point in history".
I think using
git archive "$commit" --format=tar |
{ cd "$output_directory" && tar -xf -; }
is probably the simplest solution. If you don't want to rely on tar then
something like
GIT_DIR="$(git rev-parse --path-format=absolute --git-dir)" &&
GIT_COMMON_DIR="$(git rev-parse --path-format=absolute
--git-common-dir)" || exit
GIT_INDEX_FILE="$GIT_DIR/tmp-index-$$"
export GIT_DIR GIT_COMMON_DIR GIT_INDEX_FILE
unset GIT_WORK_TREE
mkdir "$output_directory" && cd "$output_directory" &&
git read-tree -u "$commit"
status=$?
rm "$GIT_INDEX_FILE"
exit $status
Which uses a temporary index file should work (note I haven't tested
it). You may want to add "--recurse-submodules" and/or
"--no-sparse-checkout" to the "git read-tree" commandline.
Best Wishes
Phillip
> IMO all possible solutions are summarized in this thread
> https://stackoverflow.com/questions/160608/do-a-git-export-like-svn-export
> I describe some of them with my remarks:
>
> - git checkout-index : works with HEAD only.
> - git archive: influenced by export-ignore and export-subst
> attributes, so may not produce exact copy of sources. (And needs tar).
> - git worktree add -d : needs cleanup: git prune or git remove.
> - git clone: Unfortunately, -b param cannot work with commit hash and
> does not respect local worktree settings (e.g. autocrlf). So, a
> solution may be a bit complicated: git clone -s -n . dest/path ; cp
> .git/config dest/path/.git ; cd dest/path ; git co -q <commit-ish> ;
> rm -rf .git
> - git checkout: Unfortunately, modifies Git index, so some action to
> revert index is necessary after: git --work-tree=/path/to/checkout/
> checkout -f -q <tree-ish> -- ./
>
> For me, the best solution is with git clone, because it does not
> modify Git index nor any source working tree settings, so no cleanup
> is necessary. But it's a bit complicated, though. It seems to me that
> "git checkout" could do this better and simpler if it would have some
> param to not modify the Git index. Is it possible to enhance git
> checkout? Or is there any other simple solution not mentioned in the
> SO thread?
>
> Thank you
> Ondra Medek
>
next prev parent reply other threads:[~2024-05-13 15:28 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2024-05-13 7:26 Checkout to different directory at certain commit without changing index Ondra Medek
2024-05-13 15:28 ` Phillip Wood [this message]
2024-05-13 17:23 ` Ondra Medek
2024-05-14 6:29 ` Ondra Medek
2024-05-14 10:07 ` phillip.wood123
2024-05-15 5:07 ` Ondra Medek
2024-05-14 10:01 ` phillip.wood123
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