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From: "Santi Béjar" <santi@agolina.net>
To: Pascal Obry <pascal@obry.net>
Cc: Git Mailing List <git@vger.kernel.org>
Subject: Re: Finding the name of the parent branch?
Date: Fri, 30 Jan 2009 14:57:05 +0100	[thread overview]
Message-ID: <adf1fd3d0901300557t19ca4bccn7fe24013a05d2d57@mail.gmail.com> (raw)
In-Reply-To: <a2633edd0901300535mf2d9ceemd9e9009e0aa18b40@mail.gmail.com>

2009/1/30 Pascal Obry <pascal@obry.net>:
> Santi,
>
>> Maybe if you explain why you want it (a use case) instead of just this
>> specific problem...
>
> To know the proper merge base to display all commits done on a specific
> topic branch.
>

gitk topicbranch ^trackingbranch

But I agree that a way to refer to the tracking branch would be great, as:

branch^{origin}

so you can say, for example:

gitk topicbranch ^topicbranch^{origin}

>>>> Just a counterexample, just rearranging you graph:
>>>>
>>>>                        o---B
>>>>                        /
>>>>                   o---2---o---o---o---C
>>>>                  /
>>>>          ---o---1---o---o---o---A
>>>>
>>>> From you description: For B I would get C and for C I would get A.
>>
>> Please, if you quote text do not edit it (the 1 and the 2 in this case).
>
> Well I've just added 1 and 2, nothing changed in the semantic!
>
>> Yes. Compare your sentence and mine:
>>
>> For B I want to get A and for C I want to get B.
>> For B I would get C and for C I would get A.
>>
>> So for B you get A while I get C, and the equivalent for C.
>
> Ok, that's expected since you have renamed B to C and C to B.

I did not rename B to C and C to B, I just draw them differently.

Let's put name to the commits:

Your tree:


                        i---j---k---C
                        /
                   f---g---h---B
                  /
          ---a---b---c---d---e---A

My tree:

                       h---B
                       /
                  f---g---i---j---k---C
                 /
         ---a---b---c---d---e---A

So the commits in all the branches are equal, the only change is that
I painted B above C.

> So when I said:
>
>    For B I want to get A and for C I want to get B.
>
> It is equivalent to your (just rename B and C).:
>
>   For B I would get C and for C I would get A.
>
> Frankly I do not see your point... That's maybe the cause of the
> problem I'm having....

At least part of. You have to understand the branch model:

git model:
  * a branch is just a pointer to a commit
  * you cannot say "this commit was done in that branch"
  * what you can say is "this commit is contained in that branch"

in contrast to other models:
  * where a commit really belongs to a branch (it is specified at
commit time somehow)
  * you can say "this commit was done in that branch"

HTH,
Santi

  reply	other threads:[~2009-01-30 13:58 UTC|newest]

Thread overview: 11+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2009-01-30 10:56 Finding the name of the parent branch? Pascal Obry
2009-01-30 11:18 ` Santi Béjar
2009-01-30 12:56   ` Pascal Obry
2009-01-30 13:16     ` Santi Béjar
2009-01-30 13:35       ` Pascal Obry
2009-01-30 13:57         ` Santi Béjar [this message]
2009-01-30 14:06           ` Pascal Obry
2009-01-30 14:46             ` Santi Béjar
2009-01-30 13:35     ` Michael J Gruber
2009-01-30 14:26 ` Thomas Koch
2009-01-30 15:58   ` Pascal Obry

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