Re: git clone -l

[Daniel Barkalow <barkalow@iabervon.org>]

On Tue, 4 Mar 2008, Junio C Hamano wrote:

> Daniel Barkalow <barkalow@iabervon.org> writes:
> 
> > What, exactly, is -l supposed to do for clone? As far as I can tell, we 
> > automatically do the local magic if we can. Would it be okay to make 
> > "local" default to "if possible", have "-l" mean error if not possible, 
> > and have "--no-local" able to avoid using local magic even if we could use 
> > it?
> 
> It used to be that "-l" meant "When it is local, use hardlink if possible
> otherwise copy without complaining, as either are cheaper than the pack
> piped to unpack."  Lack of -l meant no local magic.
> 
> Recently lack of -l stopped to mean "no local magic".  We still do the
> local magic, but we do not do hardlinks and instead do copies.  An "-l"
> that asks clone across filesystems still falls back to copying but now
> gets a warning.  "--no-hardlinks" does not have any significance anymore,
> as that is what you would get for a local clone without -l.
> 
> The way to refuse local magic is to use file://$path/ explicitly; we do
> not have --no-local.

Ah, okay. I was having a hard time getting the not-using-local-magic case 
to be clearly not using local magic, but I think that was confusion on my 
part. Also, it looks like we need a test that not using -l is equivalent 
to --no-hardlinks.

Would it be okay to additionally block local magic, even with a local 
path, if "--no-local" is used? Using our parse-options code means 
--no-local is accepted anyway, and it's a bit confusing that it doesn't 
block default local magic. (Obviously, this won't break anything, since 
old code wouldn't have accepted it.)

	-Daniel
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