Re: [Bug] In `git-rev-list(1)`, using the `--objects` flag doesn't work well with the `--not` flag, as non-commit objects are not excluded

[Junio C Hamano <gitster@pobox.com>]

Karthik Nayak <karthik.188@gmail.com> writes:

> The provided reproduction recipe unfortunately uses a linear
> history and therefore, is not the same as the example provided by
> me. Here is a reproducible recipe following the same commands you
> used:
> $ rm -fr new ; git init new ; cd new
> $ echo foo >foo
> $ git add -A; git commit -m one; git rev-parse HEAD
> 26fb965d7439c1760677377bf314d8933de0b716
> $ mkdir bar; echo goo >bar/goo
> $ git add -A; git commit -m two; git rev-parse HEAD
> $ git checkout -B branch
> $ git reset --hard @~1
> HEAD is now at 26fb965 one
> $ git add -A; git commit -m three; git rev-parse HEAD
> 91ef508167eb683486c3df6f8d07622b61ed698d
>
> $ git rev-list --objects HEAD ^master
> 91ef508167eb683486c3df6f8d07622b61ed698d
> ff05824d2f76436c61d2c971e11a27514aba6948
> 8baef1b4abc478178b004d62031cf7fe6db6f903 abc
> 086885f71429e3599c8c903b0e9ed491f6522879 bar
> 7a67abed5f99fdd3ee203dd137b9818d88b1bafd bar/goo

Thanks, but the above is not recreating the same as your original
(where did "moo" go???).  Also "git rev-parse HEAD" for the sanity
checking should be spelled "git rev-parse HEAD:" if you want to help
others looking into the issue---anybody trying to reproduce will NOT
have the same commit object name, but the point of these checks is
to show the tree object name, which should reproduce for them.