Re: [igt-dev] [PATCH i-g-t] lib: Don't leak children in igt_waitchildren_timeout

[Daniel Vetter <daniel@ffwll.ch>]

On Tue, Feb 12, 2019 at 12:09:25PM +0000, Chris Wilson wrote:
> Quoting Daniel Vetter (2019-02-12 12:04:29)
> > Instead of cleaning up the mess in igt_exit make sure we don't even
> > let it out of the container. See also
> > 
> > commit 754876378d6c9b2775e8c07b4d16f9878c55949f
> > Author: Chris Wilson <chris@chris-wilson.co.uk>
> > Date:   Fri Feb 26 22:11:10 2016 +0000
> > 
> >     igt/gem_sync: Enforce a timeout of 20s
> > 
> > which added this helper.
> > 
> > To make sure that everyone follows the rules, add an assert.
> > 
> > We're keeping the cleanup code as a failsafe, and because it speeds
> > up the testcase I'm following up with.
> > 
> > v2: Chris pointed out that my original patch did nothing. Which I
> > didn't catch because my testcase was also broken. Unfortunately this
> > means we need to open code part of the waiting.
> > 
> > v3: The 2nd __igt_waitchildren() isn't necessary, __igt_waitchildren
> > recovers from EINTR already and keeps waiting (Chris Wilson).
> > 
> > Cc: Chris Wilson <chris@chris-wilson.co.uk>
> > Signed-off-by: Daniel Vetter <daniel.vetter@intel.com>
> > ---
> >  lib/igt_core.c | 38 +++++++++++++++++++++++++++++++++-----
> >  1 file changed, 33 insertions(+), 5 deletions(-)
> > 
> > diff --git a/lib/igt_core.c b/lib/igt_core.c
> > index cbbe79f88070..fa73712ced91 100644
> > --- a/lib/igt_core.c
> > +++ b/lib/igt_core.c
> > @@ -1525,6 +1525,7 @@ void igt_exit(void)
> >  
> >         for (int c = 0; c < num_test_children; c++)
> >                 kill(test_children[c], SIGKILL);
> > +       assert(!num_test_children);
> >  
> >         if (!test_with_subtests) {
> >                 struct timespec now;
> > @@ -1832,20 +1833,47 @@ void igt_waitchildren(void)
> >                 igt_fail(err);
> >  }
> >  
> > +static bool igt_killchidren_timed_out;
> > +
> > +static void igt_alarm_killchildren(int signal)
> > +{
> > +       igt_info("Timed out waiting for children\n");
> > +
> > +       igt_killchidren_timed_out = true;
> > +
> > +       for (int c = 0; c < num_test_children; c++)
> > +               kill(test_children[c], SIGKILL);
> > +}
> > +
> >  /**
> >   * igt_waitchildren_timeout:
> >   * @seconds: timeout in seconds to wait
> >   * @reason: debug string explaining what timedout
> >   *
> > - * Wait for all children forked with igt_fork, for a maximum of @seconds.
> > - *
> > - * Wraps igt_waitchildren() and igt_set_timeout()
> > + * Wait for all children forked with igt_fork, for a maximum of @seconds. If the
> > + * timeout expires, kills all children and cleans them up.
> >   */
> >  void igt_waitchildren_timeout(int seconds, const char *reason)
> >  {
> > -       igt_set_timeout(seconds, reason);
> > -       igt_waitchildren();
> > +       struct sigaction sa;
> > +       int ret;
> > +
> > +       sa.sa_handler = igt_alarm_killchildren;
> > +       sigemptyset(&sa.sa_mask);
> > +       sa.sa_flags = 0;
> > +
> > +       igt_killchidren_timed_out = false;
> > +
> > +       sigaction(SIGALRM, &sa, NULL);
> > +
> > +       alarm(seconds);
> > +
> > +       ret = __igt_waitchildren();
> > +       if (!igt_killchidren_timed_out && ret)
> > +               igt_fail(ret);
> >         igt_reset_timeout();
> 
> Experience says to cancel the alarm as soon as you no longer need it.
> 
> > +       if (igt_killchidren_timed_out)
> > +               igt_fail(IGT_EXIT_FAILURE);
> 
> Something like
> 
> ret = __igt_waitchildren();
> igt_reset_timeout();
> if (igt_killchildren_timed_out && !ret) // this should be impossible!
> 	ret = IGT_EXIT_FAILURE;
> if (ret)
> 	igt_fail(ret);
> 
> Just to have only one path to the igt_fail. I'm not even sure about
> needing the igt_killchildren_timed_out; if no child was killed then we
> didn't exactly timeout :)

Hm right ordered this way we should either get a SIGKILL status in ret, or
it all worked out. I'll respin.
-Daniel
-- 
Daniel Vetter
Software Engineer, Intel Corporation
http://blog.ffwll.ch
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