fork() and exec()

* fork() and exec()
@ 2012-02-06 19:08 Vijay Chauhan
  2012-02-06 19:27 ` Jeff Haran
                   ` (2 more replies)
  0 siblings, 3 replies; 5+ messages in thread
From: Vijay Chauhan @ 2012-02-06 19:08 UTC (permalink / raw)
  To: kernelnewbies

Hi List,

I am learning Linux and trying to understand exec and fork function.
execl says that it overlays the running address space. What does it mean?

I created the following program and used top command with
intentionally wrong arguments:

#include<stdio.h>
#include<unistd.h>
#include<sys/types.h>
#include<stdlib.h>

int main(){
	int a = -1;
	if(fork()==0){
		printf("Inside child\n");
		printf("child pid=%d, parentid=%d\n", getpid(), getppid());
		execl("/usr/bin/top", "/usr/bin/top", ">/dev/null" ,(char*)0 );
		scanf("inside child provide a %d", &a);
		printf("Inside child a=%d\n", a);
		exit(1);
	} else {
		printf("Inside parent, going to wait\n");
		printf("my pid=%d, parentid=%d\n", getpid(), getppid());
		scanf("input parent %d\n", &a);
		wait(NULL);
		printf("Wait over\n");
		printf("Inside parent a=%d\n", a);
	}
	return 0;
}

When i run this program, it gives following output:
[vijay at localhost]$ ./a.out
Inside parent, going to wait
Inside child
child pid=2775, parentid=2774
my pid=2774, parentid=2681
        top: unknown argument '>'
usage:  top -hv | -bcisSHM -d delay -n iterations [-u user | -U user]
-p pid [,pid ...]

10
Wait over
Inside parent a=-1
[vijay at localhost]$

Why the child scanf and printf not executed?
In the parent program, i expected input parent should be printed. But
it doesnt and just wait for some input. When i entered 10 it resumes
but printing -1 as a value.

Could anyone please help me to understand this behavior? or any good
tutorial or book

Thanks.
Vijay

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