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From: John Wood <john.wood@gmx.com>
To: "Valdis Klētnieks" <valdis.kletnieks@vt.edu>
Cc: John Wood <john.wood@gmx.com>, kernelnewbies@kernelnewbies.org
Subject: Re: Read the "real_parent" field of task_struct
Date: Thu, 8 Oct 2020 19:05:02 +0200	[thread overview]
Message-ID: <20201008170502.GA3340@ubuntu> (raw)
In-Reply-To: <20201002165922.GA4200@ubuntu>

Hi,

On Fri, Oct 02, 2020 at 06:59:22PM +0200, John Wood wrote:
>
> static void brute_share_stats(struct brute_stats **src,
> 			      struct brute_stats **dst)
> {
> 	spin_lock(&(*src)->lock);
> 	refcount_inc(&(*src)->refc);
> 	*dst = *src;
> 	spin_unlock(&(*src)->lock);
> }
>
> static int brute_task_alloc(struct task_struct *task, unsigned long clone_flags)
> {
> 	struct task_struct *p_task;
> 	struct brute_stats **stats, **p_stats;
>
> 	p_task = task->real_parent;		/////////// <----
> 	if (unlikely(!p_task))			/////////// <----
> 		return -ESRCH;
>
> 	stats = brute_stats_ptr(task);
> 	p_stats = brute_stats_ptr(p_task);	/////////// <----
>
> 	if (likely(*p_stats)) {
> 		brute_share_stats(p_stats, stats);
> 		return 0;
> 	}
>
> 	*stats = brute_new_stats();
> 	if (!*stats)
> 		return -ENOMEM;
>
> 	brute_share_stats(stats, p_stats);
> 	return 0;
> }
>
> This code is very untested.

Now the code is tested.

> And now my first question: how can I read the
> real_parent field in a secure way. Do I need to use an rcu_read_lock()/
> rcu_read_unlock() block? Do I need to use rcu_dereference? Do I need to
> use a read_lock(&task_list_lock)/read_unlock(&task_list_lock) block?
>
> The lines with the mark are not clear to me. Sorry.

Any help would be greatly appreciated. Thanks in advance.

Regards,
John Wood

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      reply	other threads:[~2020-10-08 17:05 UTC|newest]

Thread overview: 6+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2020-09-25 16:11 Read the "real_parent" field of task_struct John Wood
2020-09-30 11:59 ` Valdis Klētnieks
2020-10-01 17:49   ` John Wood
2020-10-02  0:29     ` Valdis Klētnieks
2020-10-02 16:59       ` John Wood
2020-10-08 17:05         ` John Wood [this message]

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