From: Christoffer Dall <christoffer.dall@arm.com>
To: Marc Zyngier <marc.zyngier@arm.com>
Cc: kvmarm@lists.cs.columbia.edu,
linux-arm-kernel@lists.infradead.org, kvm@vger.kernel.org
Subject: Re: [PATCH] KVM: arm/arm64: arch_timer: Mark physical interrupt active when a virtual interrupt is pending
Date: Tue, 12 Feb 2019 17:41:38 +0100 [thread overview]
Message-ID: <20190212164138.GB4530@e113682-lin.lund.arm.com> (raw)
In-Reply-To: <20190208144300.75299-1-marc.zyngier@arm.com>
On Fri, Feb 08, 2019 at 02:43:00PM +0000, Marc Zyngier wrote:
> When a guest gets scheduled, KVM performs a "load" operation,
> which for the timer includes evaluating the virtual "active" state
> of the interrupt, and replicating it on the physical side. This
> ensures that the deactivation in the guest will also take place
> in the physical GIC distributor.
>
> If the interrupt is not yet active, we flag it as inactive on the
> physical side. This means that on restoring the timer registers,
> if the timer has expired, we'll immediately take an interrupt.
> That's absolutely fine, as the interrupt will then be flagged as
> active on the physical side. What this assumes though is that we'll
> enter the guest right after having taken the interrupt, and that
> the guest will quickly ACK the interrupt, making it active at on
> the virtual side.
>
> It turns out that quite often, this assumption doesn't really hold.
> The guest may be preempted on the back on this interrupt, either
> from kernel space or whilst running at EL1 when a host interrupt
> fires. When this happens, we repeat the whole sequence on the
> next load (interrupt marked as inactive, timer registers restored,
> interrupt fires). And if it takes a really long time for a guest
> to activate the interrupt (as it does with nested virt), we end-up
> with many such events in quick succession, leading to the guest only
> making very slow progress.
>
> This can also be seen with the number of virtual timer interrupt on the
> host being far greater than the same number in the guest.
>
> An easy way to fix this is to evaluate the timer state when performing
> the "load" operation, just like we do when the interrupt actually fires.
> If the timer has a pending virtual interrupt at this stage, then we
> can safely flag the physical interrupt as being active, which prevents
> spurious exits.
>
> Signed-off-by: Marc Zyngier <marc.zyngier@arm.com>
> ---
> virt/kvm/arm/arch_timer.c | 15 ++++++++++++---
> 1 file changed, 12 insertions(+), 3 deletions(-)
>
> diff --git a/virt/kvm/arm/arch_timer.c b/virt/kvm/arm/arch_timer.c
> index 7449651ae2e5..70c18479ccd5 100644
> --- a/virt/kvm/arm/arch_timer.c
> +++ b/virt/kvm/arm/arch_timer.c
> @@ -487,12 +487,21 @@ static inline void set_timer_irq_phys_active(struct arch_timer_context *ctx, boo
> static void kvm_timer_vcpu_load_gic(struct arch_timer_context *ctx)
> {
> struct kvm_vcpu *vcpu = ctx->vcpu;
> - bool phys_active;
> + bool phys_active = false;
> +
> + /*
> + * Update the timer output so that it is likely to match the
> + * state we're about to restore. If the timer expires between
> + * this point and the register restoration, we'll take the
> + * interrupt anyway.
> + */
> + kvm_timer_update_irq(ctx->vcpu, kvm_timer_should_fire(ctx), ctx);
>
> if (irqchip_in_kernel(vcpu->kvm))
> phys_active = kvm_vgic_map_is_active(vcpu, ctx->irq.irq);
> - else
> - phys_active = ctx->irq.level;
> +
> + phys_active |= ctx->irq.level;
> +
> set_timer_irq_phys_active(ctx, phys_active);
> }
>
> --
> 2.20.1
>
Reviewed-by: Christoffer Dall <christoffer.dall@arm.com>
prev parent reply other threads:[~2019-02-12 16:41 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2019-02-08 14:43 [PATCH] KVM: arm/arm64: arch_timer: Mark physical interrupt active when a virtual interrupt is pending Marc Zyngier
2019-02-12 16:17 ` Julien Thierry
2019-02-12 16:41 ` Christoffer Dall [this message]
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