[PATCH 03/13] KVM: x86: Allocate memslot resources during prepare_memory_region()

Sean Christopherson
2019-09-11T18:51:43Z

Allocate the various metadata structures associated with a memslot
during during kvm_arch_prepare_memory_region(), which paves the way for
removing kvm_arch_create_memslot() altogether. Moving x86's memory
allocation only changes the order of kernel memory allocations between
x86 and common KVM code.

No functional change intended.

Signed-off-by: Sean Christopherson <sean.j.christopherson@intel.com>
---
arch/x86/kvm/x86.c | 9 +++++++++
1 file changed, 9 insertions(+)

diff --git a/arch/x86/kvm/x86.c b/arch/x86/kvm/x86.c
index b4cfd786d0b6..72ec6272d7cb 100644
--- a/arch/x86/kvm/x86.c
+++ b/arch/x86/kvm/x86.c
@@ -9484,6 +9484,12 @@ void kvm_arch_free_memslot(struct kvm *kvm, struct kvm_memory_slot *free,

int kvm_arch_create_memslot(struct kvm *kvm, struct kvm_memory_slot *slot,
unsigned long npages)
+{
+ return 0;
+}
+
+static int kvm_create_memslot(struct kvm *kvm, struct kvm_memory_slot *slot,
+ unsigned long npages)
{
int i;

@@ -9561,6 +9567,9 @@ int kvm_arch_prepare_memory_region(struct kvm *kvm,
const struct kvm_userspace_memory_region *mem,
enum kvm_mr_change change)
{
+ if (change == KVM_MR_CREATE)
+ return kvm_create_memslot(kvm, memslot,
+ mem->memory_size >> PAGE_SHIFT);
return 0;
}

--
2.22.0