Re: [LARTC] Ethloop?

From: King Yung Tong <tong@cs.dal.ca>
To: lartc@vger.kernel.org
Subject: Re: [LARTC] Ethloop?
Date: Fri, 07 Jun 2002 18:36:15 +0000	[thread overview]
Message-ID: <marc-lartc-102347505312988@msgid-missing> (raw)
In-Reply-To: <marc-lartc-102340461224067@msgid-missing>

Thank you for your reply :)
I try to follow chapter 6 on your user guide.

		1:1
	      /     \ 
 	    1:2     1:12
           /   \
         1:10   1:11
        (prio1) (prio2)

If 1:12 don't have any traffic, all the BW on 1:12 can be assigned to 1:2,
is that right?

I try to put all these extra (from 1:12) to 1:10, my htb script is as
follows, and I use ethloop to test and I found that 1:10 will not get the
extra from 1:12. Could you tell me where I make a mistake? Thank you.

echo Clean all the tc setup
./tc qdisc del dev lo root
./tc qdisc add dev lo root handle 1: htb default 12

./tc class add dev lo parent 1: classid 1:1 htb rate 100kbps
./tc class add dev lo parent 1:1 classid 1:2 htb rate 40kbps
./tc class add dev lo parent 1:2 classid 1:10 htb rate 30kbps prio 0
./tc class add dev lo parent 1:2 classid 1:11 htb rate 10kbps prio 1
./tc class add dev lo parent 1:1 classid 1:12 htb rate 60kbps

echo qdisc
./tc qdisc add dev lo parent 1:10 handle 20: pfifo limit 5
./tc qdisc add dev lo parent 1:11 handle 30: pfifo limit 5
./tc qdisc add dev lo parent 1:12 handle 40: sfq perturb 10

Input for ethloop:

# lo will be used to TX and RX
0       i       0       lo
0       i       1       lo
0       i       2       lo
# set simulation packet size to 1k
0       S       0       1k
0       S       1       1k
0       S       2       1k
# flow 0 AE, flow 1  BE, flow 2 EF
0       P       0       0x10010
0       P       1       0x10011
0       P       2       0x10012
# start all flow at defined rate
0       R       0       30000
0       R       1       10000
0       R       2       60000
# Create extra at 1:12 and borrow this to 1:2 <------?
5000    R       0       30000
5000    R       1       10000
5000    R       2       0
# 1:10 and 1:11 and 1:10 should get higher value <------?
15000    R      0       40000
15000    R       1      20000
# finish at 8sec
25000    X      0        0

Result is to long, I use gnuplot and found that 1:10 at most get 30000.

Thank you for you help.

Pat

On Fri, 7 Jun 2002, Martin Devera wrote:

> What is the problem ? use cat ethloop_script|./ethloop
> for example ..
> devik
> 
> On Thu, 6 Jun 2002, King Yung Tong wrote:
> 

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