From: "ThE PhP_KiD" <gregoriandres@yahoo.com.ar>
To: lartc@vger.kernel.org
Subject: [LARTC] esfq testing !
Date: Sat, 25 Oct 2003 22:00:27 +0000 [thread overview]
Message-ID: <marc-lartc-106711966612120@msgid-missing> (raw)
Hi,
I'm have a linux router like this:
ADSL modem-->(eth0) Linux Router (eth1)<--->LAN (6 hosts)
Since I want to apply fairness to 6 hosts LAN,
I have compiled kernel 2.4.20-8 with patch esfq 0.2
(and iproute2 with patch esfq too.)
Next, I run folow script:
--------------------------------------------
#!/usr/bin
TC="/sbin/tc"
$TC qdisc del dev eth1 root 2> /dev/null > /dev/null
$TC qdisc add dev eth1 root handle 1:0 esfq perturb 0 hash dst
$TC class show dev eth1
$TC qdisc show dev eth1
$TC filter show dev eth1
--------------------------------------------
And it shows me:
qdisc esfq 1: quantum 1514b hash: dst
Next, I make test from server to LAN hosts,
and put iptraf in order to make measures.
when I do:
# nohup ping 192.168.1.3 -f & (a LAN HOST)
# nohup ping 192.168.1.6 -f & (other LAN HOST)
iptraf shows me equal bandwidth to that hosts.
but if I repeat pings for one of that hosts:
# nohup ping 192.168.1.6 -f & (other LAN HOST)
# nohup ping 192.168.1.6 -f & (other LAN HOST)
# nohup ping 192.168.1.6 -f & (other LAN HOST)
iptraf shows me that 192.168.1.6 get more bandwidth
that 192.168.1.3
Then seems ESFQ behaviour is like SFQ...
what is wrong ????
I have ESFQ compiled like module.
Also I've tried put ESFQ inside a HTB class but
ESFQ behaviour is equal like above example.
Where is the problem ?
Thank you !!!
Mac
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