From: "Rafael J. Wysocki" <rjw@sisk.pl>
To: Alan Stern <stern@rowland.harvard.edu>
Cc: Zhang Rui <rui.zhang@intel.com>,
Linux Kernel Mailing List <linux-kernel@vger.kernel.org>,
linux-pm <linux-pm@lists.linux-foundation.org>,
linux-acpi <linux-acpi@vger.kernel.org>,
Pavel Machek <pavel@ucw.cz>, Len Brown <lenb@kernel.org>,
Arjan van de Ven <arjan@linux.intel.com>,
"dtor@mail.ru" <dtor@mail.ru>
Subject: Re: [PATCH V2 0/4] introduce device async actions mechanism
Date: Wed, 12 Aug 2009 01:17:27 +0200 [thread overview]
Message-ID: <200908120117.27961.rjw@sisk.pl> (raw)
In-Reply-To: <Pine.LNX.4.44L0.0908111438230.5845-100000@iolanthe.rowland.org>
On Tuesday 11 August 2009, Alan Stern wrote:
> On Tue, 11 Aug 2009, Rafael J. Wysocki wrote:
>
> > > The general algorithm for maximum parallelism goes as follows: Start by
> > > resuming (in parallel) all the devices which don't depend on anything
> > > else. Each time a resume finishes, you go on to resume (in parallel)
> > > all the devices which depend only on resumed devices and which haven't
> > > yet started to resume.
> > >
> > > As described, this can require a large number of threads. It also
> > > requires detailed knowledge of which devices depend on others, which we
> > > don't have.
> >
> > It's even more complicated than that.
> >
> > Assume we have 7 devices, A-G, such that A is the parent of B and C,
> > B is the parent of D and E, and C is the parent of F and G. Assume in addition
> > that the PM dependencies between the devices are fully reflected by the
> > device tree structure (ie. there are no dependencies that aren't reflected
> > parent-child relationships) and that B and G take 0.5 s to resume while the
> > others take < 1 ms each. So, the total sequential resume time is
> > 2 s + O(1 ms).
> >
> > Now, if we used the above algorithm, we'd first resume DEFG which would take
> > 1 s because of G, then we'd resume BC which would take 1 s because of B and
> > the total resume time is again 2 s + O(1 ms).
>
> (You probably mean "suspend" instead of "resume".)
Yes, I got it the other way around here, sorry.
> No, you misunderstood my description. We'd start out by suspending
> DEFG. DEF will finish quickly, at which time we would start suspending
> B because all its dependencies are satisfied. When G finishes we would
> start suspending C. When B and C are both finished, we would suspend
> A. Total time would be about 1 s because B would be started shortly
> after G.
Ah, OK.
> > However, one can observe that B doesn't need to wait for G to resume, because
> > they are independent of each other. So, we can resume BDE in parallel with
> > CFG, while of course DE have to wait for B and so on, but this way we can
> > theoretically reduce the total resume time to 1 s + O(1 ms).
> >
> > The question is how to do that and it seems to me that we can use completions
> > for this purpose. Namely, add a completion to each device with the following
> > rules:
> > 1) all completions are reset before dpm_resume(),
> > 2) before executing the ->resume() callback for device D, we wait for the
> > completion of the D's parent,
> > 3) we complete the D's completion after executing its ->resume() callback.
> > Also, the items executed in parallel are now the "wait for the parent's
> > completion, run our callback and complete our completion" things.
>
> Yes, that's essentially what I described.
Good.
> > At first sight I don't see anything fundamentally wrong with this approach.
>
> Nothing fundamentally wrong. The problems come in the details. Most
> notably, the dependencies that are not reflected in the tree structure.
>
> In practice, rather than completions I'd recommend using a pool of
> threads together with a single wait queue and a list of devices which
> _might_ be ready. Initially this list can contain every device.
>
> Each time a thread wakes up it scans the list, removing devices that
> aren't actually ready yet (i.e., the dependencies aren't satisfied).
> If it doesn't find any devices that are ready, it goes back to sleep.
> When it finds a device that _is_ ready, it wakes up another thread and
> invokes the callback. When the callback is done, the thread adds to
> the list all devices that depend on the one just finished. Then it
> goes back to scanning the list.
That looks quite complicated at first sight, but asynchronous resume with
completions can be done in a relatively simple patch. I've got one, so
tomorow I'll post it for further discussion.
Thanks,
Rafael
PS
Did you have a chance to look at rev. 15 of the runtime PM patch
(http://patchwork.kernel.org/patch/40306/)?
next prev parent reply other threads:[~2009-08-11 23:17 UTC|newest]
Thread overview: 24+ messages / expand[flat|nested] mbox.gz Atom feed top
2009-07-24 3:01 [PATCH V2 0/4] introduce device async actions mechanism Zhang Rui
2009-08-03 21:18 ` Rafael J. Wysocki
2009-08-04 3:35 ` Zhang Rui
2009-08-04 16:21 ` Rafael J. Wysocki
2009-08-04 17:33 ` Alan Stern
2009-08-04 18:44 ` Rafael J. Wysocki
2009-08-05 1:47 ` Zhang Rui
2009-08-07 23:42 ` Rafael J. Wysocki
2009-08-05 2:24 ` Zhang Rui
2009-08-08 0:22 ` Rafael J. Wysocki
2009-08-08 0:29 ` Dmitry Torokhov
2009-08-08 12:53 ` Rafael J. Wysocki
2009-08-11 6:22 ` Zhang Rui
2009-08-11 15:34 ` Rafael J. Wysocki
2009-08-11 15:53 ` Alan Stern
2009-08-11 18:12 ` Rafael J. Wysocki
2009-08-11 18:59 ` Alan Stern
2009-08-11 23:17 ` Rafael J. Wysocki [this message]
2009-08-12 14:03 ` Alan Stern
2009-08-12 20:10 ` Rafael J. Wysocki
2009-08-12 20:34 ` Alan Stern
2009-08-12 21:18 ` Rafael J. Wysocki
2009-08-13 14:30 ` Alan Stern
2009-08-13 17:53 ` Rafael J. Wysocki
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