From mboxrd@z Thu Jan  1 00:00:00 1970
From: Mat Harris <mat.harris@genestate.com>
Subject: Re: oldest file
Date: Thu, 6 Feb 2003 17:16:20 +0000
Sender: linux-admin-owner@vger.kernel.org
Message-ID: <20030206171620.GA15918@genestate.com>
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To: Scott Taylor <scott@dctchambers.com>
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i meant that more pictures could be taken on one day than others. I already
know perl but the perl lists haven't got any ideas.

Let me try it from another angle. I want to keep disk usage at percentage
level defined in $x.

I want to delete the oldest day in order to keep this level. I have to
delete one day at a time, and only if a second usage check also show above
the level, can i delete another day.

I have to keep deletetions to a minimum while keeping the disk healthy as
people will want to keep their archives for as long as possible.

On Thu, Feb 06, 2003 at 08:55:07 -0800, Scott Taylor wrote:
> At 08:42 AM 2/06/03, Mat Harris wrote:
> >yes but the problem with that is that the day could be of variable size =
and
> >I can't remove more than necessary so removing day 20 may be equivalent =
to
> >removing days 19-15
>=20
> You will need to learn Perl if you are trying to compare file names. I'm=
=20
> not sure how a day can be of variable size; unless there are more than 24=
=20
> hours in some days and less in others?  Otherwise, the filesystem knows t=
he=20
> date the file was created and or modified, I don't understand why you=20
> couldn't utilize that (ls -alt).
>=20
> Perhaps I still don't understand what you are trying to do; maybe another=
=20
> attempt at an example will help.
>=20
> Scott.
>=20
>=20
> -
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--=20
Mat Harris			OpenGPG Public Key ID: C37D57D9
mat.harris@genestate.com	www.genestate.com=09

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