Re: bash question

[Jeff Largent <jlargent@imagelinks.com>]

And just to show another way:

#!/bin/bash

for i in `seq 1 10`; do
    if [ $((${i} % 2)) != 0 ]; then
       echo ${i}
    fi
done



Luca Ferrari wrote:
> On Thursday 01 April 2004 02:45 Scott@Charter's cat walking on the keyboard  
> wrote:
> 
> 
>>I can't get this bash script to work.  It's suppose to print all odd
>>numbers from 1 to 10.
>>
>>#!/usr/bin/bash
>>
>>LIMIT=10
>>a=1
>>
>>while [ "$a" -le $LIMIT ]
>>do
>>  if [ "$a" -eq $(1 3 5 7 9) ]     <---------Something not right here.
> 
> 
> This is an awkard way to print all odd numbers, have a look at this:
> 
> #!/bin/bash
> 
> LIMIT=10
> a=1
> 
> while test ${a} -lt ${LIMIT}
> do
>   go=`expr ${a} % 2`
>   if test ${go} -ne 0
>       then
>       echo "Odd number ${a}"
>   fi
> 
>   a=`expr ${a} + 1`
> 
> done
> 
> 
> exit 0
> 
> 
> In this example, if you change the LIMIT value to 100, the script will print 
> you all odds numbers, while in your example you have to put numbers by your 
> own. In perl it can result as:
> 
> #!/usr/bin/perl
> 
> $LIMIT=10;
> $a=1;
> 
>     while( $a < $LIMIT ){
>         if( ($a % 2) !=0 ){
>             print "Odd number $a\n";
>         }
>         $a++;
>     }
> 
> exit;
> 
> 
> Luca
> 
> 

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Jeff Largent                   ImageLinks, Inc.
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