Re: bash question

[Stephen Samuel <samuel@bcgreen.com>]

I'm going to presume that you want to search for a
specific set of numbers, and that the fact that the
fact that they're odd doesn't matter....

In that case, you'd have to use a for loop to seach
thru the list of 'important' values:

for $tval in 1 3 5 7 9; do
	if [ $a -eq $tval ]
	  then
		echo -n "$a "
	fi
done

As far as I know, there's no fast way to search for
one value in a list of candidates.

Scott@Charter wrote:
> I can't get this bash script to work.  It's suppose to print all odd numbers
> from 1 to 10.
> 
> #!/usr/bin/bash
> 
> LIMIT=10
> a=1
> 
> while [ "$a" -le $LIMIT ]
> do
>   if [ "$a" -eq $(1 3 5 7 9) ]     <---------Something not right here.
>     then
>       echo -n "$a "
>     fi
> 
> echo
> 
> let "a+=1"
> done
> echo; echo
> exit 0
> 
> 
> Can anyone figure out what I am doing wrong?  Can I also see the same thing
> written in Perl?


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Stephen Samuel +1(604)876-0426                samuel@bcgreen.com
		   http://www.bcgreen.com/~samuel/
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