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From: Nikolay Borisov <nborisov@suse.com>
To: linux-api@vger.kernel.org
Cc: Ext4 Developers List <linux-ext4@vger.kernel.org>,
	linux-btrfs <linux-btrfs@vger.kernel.org>,
	Ted Ts'o <tytso@mit.edu>
Subject: exporting uuid_t from uapi/linux/uuid.h
Date: Tue, 21 Aug 2018 22:25:50 +0300	[thread overview]
Message-ID: <ffc387b8-09f5-537a-c5a9-08ec28e088e0@suse.com> (raw)

Hello,

I'm doing some refactoring on btrfs and would like to convert some of
the "naked" definition of UUID in on-disk object to uuid_t. Since those
structs are defined in include/uapi/linux/btrfs_tree.h I naturally would
need to expose the kernel uuid_t to the uapi header via
include/uapi/linux/uuid.h. The uuid was originally unexported in
60927bc31436 ("uuid: remove uuid_be defintions from the uapi header")
 but at that time it was called uuid_be. The thing is that btrfs-progs
for example uses both btrfs_tree.h uapi header as well as libuuid. THe
latter also defines uuid_t. Both the kernel one and libuuid are binary
compatible.

So what's the correct way (if any) to expose a kernel type that might
have also been defined by a userspace library?

Regards,
Nikolay

             reply	other threads:[~2018-08-21 19:25 UTC|newest]

Thread overview: 2+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2018-08-21 19:25 Nikolay Borisov [this message]
2018-08-22  6:05 ` exporting uuid_t from uapi/linux/uuid.h Christoph Hellwig

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