From mboxrd@z Thu Jan 1 00:00:00 1970 From: anton.bondarenko.sama@gmail.com (Anton Bondarenko) Date: Thu, 5 Nov 2015 17:51:09 +0100 Subject: [PATCH v3 1/7] spi: imx: Fix DMA transfer In-Reply-To: <20151105083422.GH8526@pengutronix.de> References: <1446388901-6073-1-git-send-email-anton.bondarenko.sama@gmail.com> <1446388901-6073-2-git-send-email-anton.bondarenko.sama@gmail.com> <20151105083422.GH8526@pengutronix.de> Message-ID: <563B88FD.8050702@gmail.com> To: linux-arm-kernel@lists.infradead.org List-Id: linux-arm-kernel.lists.infradead.org On 05.11.2015 09:34, Sascha Hauer wrote: > On Sun, Nov 01, 2015 at 03:41:35PM +0100, Anton Bondarenko wrote: >> From: Anton Bondarenko >> >> RX DMA tail data handling doesn't work correctly in many cases with >> current implementation. It happens because SPI core was setup >> to generates both RX watermark level and RX DATA TAIL events >> incorrectly. SPI transfer triggering for DMA also done in wrong way. >> >> SPI client wants to transfer 70 words for example. The old DMA >> implementation setup RX DATA TAIL equal 6 words. In this case >> RX DMA event will be generated after 6 words read from RX FIFO. >> The garbage can be read out from RX FIFO because SPI HW does >> not receive all required words to trigger RX watermark event. >> >> New implementation change handling of RX data tail. DMA is used to process >> all TX data and only full chunks of RX data with size aligned to FIFO/2. >> Driver is waiting until both TX and RX DMA transaction done and all >> TX data are pushed out. At that moment there is only RX data tail in >> the RX FIFO. This data read out using PIO. > > Have you looked at the RX_DMA_LENGTH and RXTDEN fields of the DMA > register? These seem to be for handling the remaining bytes of a DMA > transfer which do not reach the watermark level. From reading the > documentation I haven't really understood how it works though. > > Sascha > A lot of times. Current implementation is trying to use it, but works incorrectly if length % WML != 0 (which means RX_DMA_LENGTH == 0). Regards, Anton