Re: [PATCH v4 04/13] dma: swiotlb: track pool encryption state and honor DMA_ATTR_CC_SHARED

[Mostafa Saleh <smostafa@google.com>]

On Tue, May 19, 2026 at 10:29:11AM -0300, Jason Gunthorpe wrote:
> On Tue, May 19, 2026 at 11:04:37AM +0000, Mostafa Saleh wrote:
> > On Thu, May 14, 2026 at 08:13:25PM +0530, Aneesh Kumar K.V wrote:
> > > >> 
> > > >> What I meant was that we need a generic way to identify a pKVM guest, so
> > > >> that we can use it in the conditional above.
> > > >
> > > > I have this patch, with that I can boot with your series unmodified,
> > > > but I will need to do more testing.
> > > >
> > > 
> > > Thanks, I can add this to the series once you complete the required testing.
> > > 
> > 
> > I am still running more tests, but looking more into it. Setting
> > force_dma_unencrypted() to true for pKVM guests is wrong, as the
> > guest shouldn’t try to decrypt arbitrary memory as it can include
> > sensitive information (for example in case of virtio sub-page
> > allocation) and should strictly rely on the restricted-dma-pool
> > for that.
> 
> ??
> 
> Where does force_dma_unencrypted() cause arbitary memory passed into
> the DMA API to be decrypted? That should never happen???

Sorry, maybe arbitrary is not the right expression again :)
I mean that, with emulated devices that use the DMA-API under pKVM,
they will map memory coming from other layers (VFS, net) through
vitrio-block, virtio-net... These can be smaller than a page, and
using force_dma_unencrypted() will share the whole page.
And as discussed, that leaks sensitive information to the untrusted
host.
I am currently investigating passing iova/phys/size
to force_dma_unencrypted() and then we can share pages inplace only
if possible without leaking extra information.
I am trying to get some performance results first. But the tricky part
is to get the semantics right, I believe in that case those devices
shouldn’t use restricted-dma-pools as those should always force
bouncing. Instead bouncing happens through the default SWIOTLB pool,
if not possible to decrypt in place.

Thanks,
Mostafa

> 
> Jason