From mboxrd@z Thu Jan  1 00:00:00 1970
From: ishare <june.tune.sea@gmail.com>
Subject: Re: how does ld.so call ELF's entry?
Date: Sun, 7 Apr 2013 11:39:13 +0800
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To: Sofiane Akermoun <akersof@gmail.com>
Cc: linux-assembly@vger.kernel.org

On Sun, Apr 07, 2013 at 05:11:28AM +0200, Sofiane Akermoun wrote:
> Hello,
> 
> 
> The interpreter is specified during linking process and the program header
> of your binary is filled with good values.
> Then when the operating system load your binary, he finds next the
> interpreter to use.
> The linker ld sets the good values by default but you can overwrite it or
> specify other values if you want.
> The steps are:
> 1)The operating system loads your binary
> 2)The program loader system execute the Interpreter specifiy in the binary
> 3)The interpreter gather all the dynamic libraries needed in memory


> 4)The Control is passed to the entry point of your program

  How does  the step 4 been  done ?
  
  thanks!
> 
> The entry point is specified in your code source as a "global". And could
> be find in your object file by the linker.
> In theory there are some default tag to specify entry point, like "..start"
> for nasm, but you can also passed it to the linker.
> 
> regards,
> 
> Sofiane Akermoun
> akersof@gmail.com
> 
> 
> 
> 
> 
> 2013/4/7 ishare <june.tune.sea@gmail.com>
> 
> >
> >   For an ELF ,which needs a interpreter , how is it  been called by the
> > interpreter ?
> >
> >   As I know the interpreter is loaded first and do something essential
> > ,then call the main routine of ELF .
> >   How is this procedure implemented ?
> >
> >   Thanks!
> > --
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> >
> 
> 
> 
> -- 
> Sofiane AKERMOUN
> akersof@gmail.com