Re: how does ld.so call ELF's entry?

[ishare <june.tune.sea@gmail.com>]

On Sat, Apr 06, 2013 at 08:43:16PM -0700, Chris Evans wrote:
> With a far jump to entry offset 

  How does it know the entry point's address?

> 
> 
> Sent from my iPad
> 
> On Apr 6, 2013, at 8:39 PM, ishare <june.tune.sea@gmail.com> wrote:
> 
> > On Sun, Apr 07, 2013 at 05:11:28AM +0200, Sofiane Akermoun wrote:
> >> Hello,
> >> 
> >> 
> >> The interpreter is specified during linking process and the program header
> >> of your binary is filled with good values.
> >> Then when the operating system load your binary, he finds next the
> >> interpreter to use.
> >> The linker ld sets the good values by default but you can overwrite it or
> >> specify other values if you want.
> >> The steps are:
> >> 1)The operating system loads your binary
> >> 2)The program loader system execute the Interpreter specifiy in the binary
> >> 3)The interpreter gather all the dynamic libraries needed in memory
> > 
> > 
> >> 4)The Control is passed to the entry point of your program
> > 
> >  How does  the step 4 been  done ?
> > 
> >  thanks!
> >> 
> >> The entry point is specified in your code source as a "global". And could
> >> be find in your object file by the linker.
> >> In theory there are some default tag to specify entry point, like "..start"
> >> for nasm, but you can also passed it to the linker.
> >> 
> >> regards,
> >> 
> >> Sofiane Akermoun
> >> akersof@gmail.com
> >> 
> >> 
> >> 
> >> 
> >> 
> >> 2013/4/7 ishare <june.tune.sea@gmail.com>
> >> 
> >>> 
> >>>  For an ELF ,which needs a interpreter , how is it  been called by the
> >>> interpreter ?
> >>> 
> >>>  As I know the interpreter is loaded first and do something essential
> >>> ,then call the main routine of ELF .
> >>>  How is this procedure implemented ?
> >>> 
> >>>  Thanks!
> >>> --
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> >> 
> >> 
> >> 
> >> -- 
> >> Sofiane AKERMOUN
> >> akersof@gmail.com
> > --
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