From: Steve Grubb <sgrubb@redhat.com>
To: linux-audit@redhat.com
Subject: Re: audit review question
Date: Thu, 28 Apr 2016 11:09:51 -0400 [thread overview]
Message-ID: <5168316.VjEz05O2MH@x2> (raw)
In-Reply-To: <BY1PR09MB08876A7BF5D3D5824EA00409C7640@BY1PR09MB0887.namprd09.prod.outlook.com>
On Wednesday, April 27, 2016 09:10:39 PM Warron S French wrote:
> I have a scenario that I need a little help understanding how to work
> through in an isolated environment of 1 server and 6 workstations (7
> machines). The 7 machines are all running CentOS-6.7 and selinux =
> disabled.
>
> All 6 workstations are configured through rsyslog.conf to send audit data to
> the server, and I have (but apparently not successfully configured general
> system messages to also report back to the same server). I am using the
> conventional filesystems for each, but the directory structure below is
> different.
Rsyslog will likely mangle the audit lines such that its no longer in the
native audit format. I don't know if its headers can be stripped as it writes
to disk.
> For audit, I use, /var/log/audit/2016/04/27/wk{1..6}_audit.log the
> directory per day and per month and per year are auto created
> (miraculously). For system messages, and I know this isn't the forum to get
> help on this so I will only list the directory is -
> /var/log/2016/04/27/wk{1..6}_syslog.log.
>
> Now that I am doing this, and successfully, I want to test that the security
> auditors will be able to do their job properly, as well as I am trying to
> comply with some security constraint that requires me to centralize the
> logdata into a single server (hence the major driver for all of this).
>
> I know that there is the aureport and ausearch command, but I am not sure
> that I am able to figure out the correct command-line structure to test
> that audit-data is getting into the appropriate file, on each day of the
> year, on a per serverName basis.
>
> If a real-world situation occurred that the Security Auditors were asking to
> find out how many machines did userX attempt to log into, what would be the
> appropriate command for the example audit directory I listed above
> (/var/log/audit/2016/04/27/wk{1..6}_audit.log), because I am not sure I am
> running the command with the appropriate switches to scan the files
> properly?
>
> I used:
>
> * aureport -if /var/log/audit/2016/04/27/ and it didn't like the
> input,
Probably due to the header it inserts to each record. But this is how you
should do it.
> * aureport -if /var/log/audit/2016/04/27/* and it didn't like the
> input, am I using the command improperly?
You shouldn't need the '*'. If the passed option is a dir, then it
automatically looks for more files. But note that the native rotation is
audit.log <- newest
audit.log.1
audit.log.2
audit.log.3 <- oldest
rsyslog would also have to use this scheme. I have never investigated if it
does. That does not means that a wrapper script couldn't be made to walk the
files in rsyslog's order and send them to aureport via stdin. You could
probably even add a sed command to strip the rsyslog headers from each record.
Not the best answer, but once it hits rsyslog, it can change the record in
ways that unknown to me.
-Steve
next prev parent reply other threads:[~2016-04-28 15:09 UTC|newest]
Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top
2016-04-27 21:10 audit review question Warron S French
2016-04-28 15:09 ` Steve Grubb [this message]
2016-04-28 15:50 ` Warron S French
2016-04-29 19:18 ` Steve Grubb
2016-04-29 20:21 ` Warron S French
2016-05-03 18:28 ` Warron S French
2016-05-03 18:53 ` Steve Grubb
2016-05-03 19:30 ` Warron S French
2016-05-03 19:38 ` Steve Grubb
2016-05-03 19:54 ` Warron S French
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