Re: [Bluez-devel] finding the least busy hci device

["Benjamin Fong" <benjamin.backup@gmail.com>]

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I'm afraid the logic we'd both employed is pretty identical. Instead of
using bash script, I've a method within my obex application which will
iteratively examine each hci device and return the first hci device which
has less than X amount of connected device to it.


static int is_dev_available(int dev_id)
{
 struct hci_conn_list_req *cl;
 struct hci_conn_info *ci;

 if (!(cl = malloc(10 * sizeof(*ci) + sizeof(*cl)))) {
  printf("Can't allocate memory");
  exit(1);
 }

 cl->dev_id = dev_id;
 cl->conn_num = 10;
 ci = cl->conn_info;

 if (ioctl(-1, HCIGETCONNLIST, (void *) cl)) {
  printf("Can't get connection list");
  exit(1);
 }

 if ( cl->conn_num <= 5 )
 {
  return 1;
 }

 return 0;
}

I've set the maximum allowed connection per dongle to 5 because of hardware
limitation, is there any other way which I can inquire the maximum allowed
connection per hci device via codes instead of using a magic number? Thanks



Regards,

Ben




On 5/3/07, Manuel Naranjo <naranjo.manuel@gmail.com> wrote:
>
> Williams, Richard escribió:
> > I think the solution is pretty simple, and is done entirely at the
> > application level. I wrote an app that uses multiple dongles, for HCI
> > commands, SDP and OBEX. I have an array of hci control objects that I
> > "alloc" and "free" just as you would any other shared resource.
> >
> > Whenever I need to do a BT operation, the app goes to the pool of HCI
> > devices and requests one with "hci_alloc()". If one is free, that "hciX"
> > is returned. If none is free, then NULL is returned. When the app is
> > done with the operation, I do an "hci_free()".
> >
> That's what I'm doing so far, I'm doing it all from a bash script, I
> keep the count of hci dongles I have and then open one connection one
> per hci. And I count how many hci connections each hci has.
> But that's not the best for sure.
> Thanks,
> Manuel
>
>
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