From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: from mo4-p00-ob.smtp.rzone.de ([81.169.146.217]:16831 "EHLO mo4-p00-ob.smtp.rzone.de" rhost-flags-OK-OK-OK-OK) by vger.kernel.org with ESMTP id S1759656AbdJQR67 (ORCPT ); Tue, 17 Oct 2017 13:58:59 -0400 Received: from mordor.fritz.box (x5f749cb2.dyn.telefonica.de [95.116.156.178]) by smtp.strato.de (RZmta 42.6 DYNA|AUTH) with ESMTPSA id i0a928t9HHwtHhO (using TLSv1.2 with cipher ECDHE-RSA-AES256-GCM-SHA384 (curve secp521r1 with 521 ECDH bits, eq. 15360 bits RSA)) (Client did not present a certificate) for ; Tue, 17 Oct 2017 19:58:55 +0200 (CEST) Message-ID: <1508263135.2887.1.camel@cloud.haefemeier.eu> Subject: Best strategie to remove devices from pool From: Cloud Admin To: linux-btrfs@vger.kernel.org Date: Tue, 17 Oct 2017 19:58:55 +0200 Content-Type: text/plain; charset="UTF-8" Mime-Version: 1.0 Sender: linux-btrfs-owner@vger.kernel.org List-ID: Hi, I want to remove two devices from a BTRFS RAID 1 pool. It should be enough free space to do it, but what is the best strategie. Remove both device in one call 'btrfs dev rem /dev/sda1 /dev/sdb1' (for example) or should it be better in two separate calls? What is faster? Are there other constraints to think about? Bye Frank