RE: Question!

["Mariano Moreyra" <moremari@aca.org.ar>]

The problem is that the child is waiting for the script to finish (the one
that start mysqld) so the child sends a response to the client telling him
that the script finished ok (or not).
So, if I close the socket, the child can't send the response.
I tried to find a solution to this situation, but the client needs to know
the exit status of the script.
The parent process has his own socket listening for incoming connections and
forks the childs. These childs accepts the connections on his own sockets,
so  childs doesn't inherit the parent's socket.
It's ok to do that?? Or I'm doing something wrong with the sockets??
Thanks a lot to all of you for your answers!!

-----Mensaje original-----
De: linux-c-programming-owner@vger.kernel.org
[mailto:linux-c-programming-owner@vger.kernel.org]En nombre de Luciano
Miguel Ferreira Rocha
Enviado el: Jueves, 04 de Septiembre de 2003 14:54
Para: Jorge Opaso Pazos
CC: linux-c-programming@vger.kernel.org
Asunto: Re: Question!


On Thu, Sep 04, 2003 at 12:04:43PM -0400, Jorge Opaso Pazos wrote:
> Mariano Moreyra wrote:
> >Hola!
> >Te mando la seccion del programa que ejecuta el script en si.
> >
> >Este proceso lo unico que espera del script es que el mismo conteste con
un
> >"-" si hubo algun error o con un "+" si salio todo bien
> >
> >----------------------------------------------------------
> >    if(err==0) {
> >      pipe_in = popen(shell_cmd,"r");
> >      fgets(response,5,pipe_in);
> >
> >      if(response[0]=='-') {
> >        err=1;
> >      } else if(response[0]=='+') {
> >        err=0;
> >      };
> >      while(fgets(response,5,pipe_in)) {
> >      };
> >      pclose(pipe_in);
> >    };
> >-----------------------------------------------------------
> >
> >El script lo unico que hace es copiar algunos archivos y luego leventar
el
> >MySQL con el
> >safe_mysqld
> >
> >Espero que esto sirva! Muchas gracias!!
> >Saludos!!
> >
> >
> >
> >-----Mensaje original-----
> >De: linux-c-programming-owner@vger.kernel.org
> >[mailto:linux-c-programming-owner@vger.kernel.org]En nombre de Jorge
> >Opaso Pazos
> >Enviado el: Miércoles, 03 de Septiembre de 2003 18:09
> >Para: linux-c-programming@vger.kernel.org
> >Asunto: Re: Question!
> >
> >
> >Mariano Moreyra wrote:
> >
> >>Hi!!
> >>First...I'd like to know if there is any kind of digest on this list to
> >
> >see
> >
> >>old submited messages.
> >>
> >>Now...I have a little problem.
> >>I have a process that is listening for incoming connections on a socket.
> >>That process waits for a command and then
> >>forks a child to run a bash script.
> >>The problems is:
> >>	- When the bash script runs the safe_mysql script to run MySql
> >>	engine,
> >
> >it's
> >
> >>like the child process never ends.
> >>	  And because of that, the parent can't close the connection with the
> >>client socket.
> >>	- But if the bash script doesn't run the safe_mysql script...the
> >>	child
> >>process dies successfully and everything end
> >>	  Ok
> >>
> >>Sorry about my english, but I hope that I made my self clear....
> >>Bye!
> >>
> >>-
> >>To unsubscribe from this list: send the line "unsubscribe
> >
> >linux-c-programming" in
> >
> >>the body of a message to majordomo@vger.kernel.org
> >>More majordomo info at  http://vger.kernel.org/majordomo-info.html
> >>
> >
> >
> >envíame el script.
> >
> >-
> >To unsubscribe from this list: send the line "unsubscribe
> >linux-c-programming" in
> >the body of a message to majordomo@vger.kernel.org
> >More majordomo info at  http://vger.kernel.org/majordomo-info.html
> >
>
> English: I suspect that the problem is that safe_mysqld don't return
> until mysqld ends.
> Try to execute safe_mysqld in background in the shellscript:
>
> 	if ! pgrep mysqld
> 	then
> 		/usr/bin/safe_mysqld &
> 	fi
As the socket is inherited, the remote client will never exit.
If the popen is after a fork(), then it doesn't matter if safe_mysql doesn't
end, as the parent wouldn't be waiting on it.

My bet is in the socket not being closed, either in the parent, child, or
both, or before the execution of safe_mysql. (If mysqld inherits the socket,
then the connection won't close until mysqld does.)

> Castellano: El problema debe ser que no termina safe_mydqld hasta que no
> termina mysqld. Se podría solucionar llamando a safe_mysqld en
> "background" de la forma anterior.

Portugues: AH! that would be something :)

Regards,
Luciano Rocha
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