From mboxrd@z Thu Jan  1 00:00:00 1970
From: "Mariano Moreyra" <moremari@aca.org.ar>
Subject: RE: const char * vs char[]
Date: Tue, 23 Mar 2004 10:44:36 -0300
Sender: linux-c-programming-owner@vger.kernel.org
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References: <20040323130118.00005637.cialdi@firenze.net>
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To: 'Massimiliano Cialdi' <cialdi@firenze.net>, 'linux-c-programming' <linux-c-programming@vger.kernel.org>

I think that the problem is not a difference between "char*" and "char[]"
The problem is that stampa is receiving a "char[]" and you are passing a
"const char*" as the arg.
The "qualifiers from pointer targer type" refers to the "const" part of the
"const char*" declaration I belive.
If you declare stampa like this:

void stampa(const char s[]);

you won't have this warning anymore.



-----Mensaje original-----
De: linux-c-programming-owner@vger.kernel.org
[mailto:linux-c-programming-owner@vger.kernel.org]En nombre de
Massimiliano Cialdi
Enviado el: Martes, 23 de Marzo de 2004 09:01
Para: linux-c-programming
Asunto: const char * vs char[]


I have this:

#include <stdio.h>
const char *str = "pippo";
int main(void)
{
  void stampa(char s[]);
  stampa(str);
  return 0;
}
void stampa(char s[])
{
 printf("%s\n", s);
}

and gcc gives me a warning:
pippo.c:9: warning: passing arg 1 of `stampa' discards qualifiers from
pointer target type


what are the differences between char[] and const char *?

thanks

--
Massimiliano Cialdi
cialdi@firenze.net
m.cialdi@oksys.it
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