Unix Time

Unix Time

[Ankit Jain]

well i dont know hot to interpret unix time

gettimeofday returns time in unix format

if i am want to subtract one time from another how to
do that?

thanks

ankit

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Re: Unix Time

[Jon Masters]

On Sun, 26 Sep 2004 20:01:04 -0700, Suciu Flavius
<suciuflavius@tiscali.de> wrote:

>   struct timeval start,stop;
>   int elapsed;
> 
>   gettimeofday(&start,NULL);
> 
>   computeWhatIWant();
> 
>   gettimeofday(&stop,NULL);
> 
> elapsed=(stop.tv_sec-start.tv_sec)*1000000+(stop.tv_usec-start.tv_usec);
> printf("sprintf:  elapsed=%5d miliseconds\n",elapsed);
 
...or you could use the POSIX difftime function if you don't mind
having a double returned.

Jon.

Re: Unix Time

[Suciu Flavius]

  struct timeval start,stop;
  int elapsed;

  gettimeofday(&start,NULL);

  computeWhatIWant();

  gettimeofday(&stop,NULL);
 
elapsed=(stop.tv_sec-start.tv_sec)*1000000+(stop.tv_usec-start.tv_usec);
printf("sprintf:  elapsed=%5d miliseconds\n",elapsed);













Ankit Jain wrote:
> well i dont know hot to interpret unix time
> 
> gettimeofday returns time in unix format
> 
> if i am want to subtract one time from another how to
> do that?
> 
> thanks
> 
> ankit
> 
> ________________________________________________________________________
> Yahoo! Messenger - Communicate instantly..."Ping" 
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> 

Re: Unix Time

[Ankit Jain]

well still the problem exists

7360568 sec how to interpret this no. in seconds?

do u know about any manula to understand htis unix
time

thanks

ankit


 --- Jon Masters <jonmasters@gmail.com> wrote: 
> On Sun, 26 Sep 2004 20:01:04 -0700, Suciu Flavius
> <suciuflavius@tiscali.de> wrote:
> 
> >   struct timeval start,stop;
> >   int elapsed;
> > 
> >   gettimeofday(&start,NULL);
> > 
> >   computeWhatIWant();
> > 
> >   gettimeofday(&stop,NULL);
> > 
> >
>
elapsed=(stop.tv_sec-start.tv_sec)*1000000+(stop.tv_usec-start.tv_usec);
> > printf("sprintf:  elapsed=%5d
> miliseconds\n",elapsed);
>  
> ...or you could use the POSIX difftime function if
> you don't mind
> having a double returned.
> 
> Jon.
> -
> To unsubscribe from this list: send the line
> "unsubscribe linux-c-programming" in
> the body of a message to majordomo@vger.kernel.org
> More majordomo info at 
> http://vger.kernel.org/majordomo-info.html
>  

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Re: Unix Time

[szonyi calin]

 --- Ankit Jain <ankitjain1580@yahoo.com> a écrit : 
> well still the problem exists
> 
> 7360568 sec how to interpret this no. in seconds?
> 
> do u know about any manula to understand htis unix
> time
> 

The linux's libc manual covers afaik the topic of time 
functions in linux/unix
also here you may find some informartion
http://www.unix.org/single_unix_specification/onlinepubs/000095399/functions/contents.html

to convert a number of secconds in actual time:
a minute has 60 seconds
an hour has 60 minutes = 3600 seconds
a day has 24 hours = 86400 seconds

Hope this helps

> thanks
> 
> ankit
> 
> 
>  

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Re: Unix Time

[Jon Masters]

On Mon, 27 Sep 2004 12:59:47 +0200 (CEST), szonyi calin
<caszonyi@yahoo.com> wrote:

> to convert a number of secconds in actual time:
> a minute has 60 seconds
> an hour has 60 minutes = 3600 seconds
> a day has 24 hours = 86400 seconds

...but don't use this because over the period of seconds since epoch
(January 1 1970 is when UNIX began counting time) it'll not take in to
account leap seconds and the like - so you'll cunningly be out of time
by a little in every calculation.

No. Use the standard POSIX time functions instead - e.g. localtime()
to give you the view of time for where you are in the world.

Cheers,

Jon.

Re: Unix Time

[Sumit Narayan]

You can use ctime() for conversion.

#include <stdio.h>
#include <time.h>
#include <stdlib.h>

int main(){
  time_t a;
  printf("%d = ", time(&a));
  printf("%s\n", ctime(&a));
  return 0;
}

Hope this helps.

--Sumit

On Mon, 27 Sep 2004 12:57:42 +0100, Jon Masters <jonmasters@gmail.com> wrote:
> On Mon, 27 Sep 2004 12:59:47 +0200 (CEST), szonyi calin
> <caszonyi@yahoo.com> wrote:
> 
> > to convert a number of secconds in actual time:
> > a minute has 60 seconds
> > an hour has 60 minutes = 3600 seconds
> > a day has 24 hours = 86400 seconds
> 
> ...but don't use this because over the period of seconds since epoch
> (January 1 1970 is when UNIX began counting time) it'll not take in to
> account leap seconds and the like - so you'll cunningly be out of time
> by a little in every calculation.
> 
> No. Use the standard POSIX time functions instead - e.g. localtime()
> to give you the view of time for where you are in the world.
> 
> Cheers,
> 
> Jon.
> 
> 
> -
> To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in
> the body of a message to majordomo@vger.kernel.org
> More majordomo info at  http://vger.kernel.org/majordomo-info.html
>