* a 'wrapper'
@ 2002-06-29 10:25 xlp
2002-06-29 14:49 ` Jan-Benedict Glaw
0 siblings, 1 reply; 3+ messages in thread
From: xlp @ 2002-06-29 10:25 UTC (permalink / raw)
To: linux-c-programming
hi, i have been trying to let certain process working on a remote machine in this way:
nohup ./a.out >> /dev/null &
but when i log off, the process dies.
Can i code a certain process that fork itself, call setsid() and run a.out with system() or exec() ?
How can i deal with this situation? I want that the executable object a.out forget about terminal control and do its work without care about sdtin/stdout/stderr.
bye Unix friends.
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: a 'wrapper'
2002-06-29 10:25 a 'wrapper' xlp
@ 2002-06-29 14:49 ` Jan-Benedict Glaw
2002-06-30 7:52 ` Ben Marsh
0 siblings, 1 reply; 3+ messages in thread
From: Jan-Benedict Glaw @ 2002-06-29 14:49 UTC (permalink / raw)
To: linux-c-programming
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On Sat, 2002-06-29 05:25:02 -0500, xlp <xlp@emtel.net.co>
wrote in message <20020629052348.A50622@nietzsche>:
> hi, i have been trying to let certain process working on a remote machine in this way:
> nohup ./a.out >> /dev/null &
> but when i log off, the process dies.
> Can i code a certain process that fork itself, call setsid() and run a.out with system() or exec() ?
> How can i deal with this situation? I want that the executable object a.out forget about terminal control and do its work without care about sdtin/stdout/stderr.
You should never ever use system(), is's insecure. Use exec*(). However,
you won't need that - try this:
nohup ./a.out > /dev/null 2>&1 < /dev/null &
It probably dies because of a SIGPIPE if it attempts to read something
from stdin or if it tries to write to stdout. You break this file
descriptors in the moment you log off...
MfG, JBG
--
Jan-Benedict Glaw . jbglaw@lug-owl.de . +49-172-7608481
-- New APT-Proxy written in shell script --
http://lug-owl.de/~jbglaw/software/ap2/
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^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: a 'wrapper'
2002-06-29 14:49 ` Jan-Benedict Glaw
@ 2002-06-30 7:52 ` Ben Marsh
0 siblings, 0 replies; 3+ messages in thread
From: Ben Marsh @ 2002-06-30 7:52 UTC (permalink / raw)
To: linux-c-programming
<I have jumped in part way through since I just subscribed.>
On Sunday, June 30, 2002, at 12:49 AM, Jan-Benedict Glaw wrote:
> On Sat, 2002-06-29 05:25:02 -0500, xlp <xlp@emtel.net.co>
> wrote in message <20020629052348.A50622@nietzsche>:
>> hi, i have been trying to let certain process working on a remote
>> machine in this way:
>> nohup ./a.out >> /dev/null &
>> but when i log off, the process dies.
>> Can i code a certain process that fork itself, call setsid() and run
>> a.out with system() or exec() ?
>> How can i deal with this situation? I want that the executable object
>> a.out forget about terminal control and do its work without care about
>> sdtin/stdout/stderr.
As I understand it you can leave a process running on another machine
after you disconnect by using nohup(1). I can only assume that it
didn't work because you try and take stdout and append to /dev/null.
The output of your command ./a.out is taken and added to nohup.out (see
man 1 nohup)
The other way that I have found that you could go is to make a.out a
daemon. This involves
1 Chdir to /
2 Close STDIN, STDOUT and STDERR.
3 Forking a new process
4 The parent exits and the child does setsid.
> You should never ever use system(), is's insecure. Use exec*(). However,
> you won't need that - try this:
>
> nohup ./a.out > /dev/null 2>&1 < /dev/null &
I believe that you should not need to use this command line.
> It probably dies because of a SIGPIPE if it attempts to read something
> from stdin or if it tries to write to stdout. You break this file
> descriptors in the moment you log off...
Now that might be it I guess. Having the append >> on your commandline
may cause this. When I use nohup the process does not exit but I don't
use '>> /dev/null'
^ permalink raw reply [flat|nested] 3+ messages in thread
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