strange gcc warning

[Shanks <mshanks79@yahoo.co.in>]

Hi,

Sample program: b.c
#include <stdio.h>
#include <errno.h>

void
my_print(int errno)
{
    printf("ERRNO: %d\n", errno);
}

int
main()
{
    int a = 10;
    errno = 0;
    my_print(a);
}

On compiling this code i get the warning:
b.c: In function `main':
b.c:15: warning: passing arg 1 of `my_print' makes pointer from integer without
a cast

On running the code i get a seg. fault. So i did some gdb'ing and got
(gdb) run 
Starting program: ./b
Breakpoint 1, my_print (__errno_location=0x19) <<<<<<<<
    at b.c, line...
(gdb)

From above i see that instead of getting a plain int its go the address.
But i would like it if someone explained it to me better.

Thanks in advance.
-S

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