From: Ankit Jain <ankitjain1580@yahoo.com>
To: jonathan@jonmasters.org
Cc: linux prg <linux-c-programming@vger.kernel.org>
Subject: Re: Unix Time
Date: Mon, 27 Sep 2004 06:10:48 +0100 (BST) [thread overview]
Message-ID: <20040927051048.25873.qmail@web52902.mail.yahoo.com> (raw)
In-Reply-To: <35fb2e590409261557361c5dea@mail.gmail.com>
well still the problem exists
7360568 sec how to interpret this no. in seconds?
do u know about any manula to understand htis unix
time
thanks
ankit
--- Jon Masters <jonmasters@gmail.com> wrote:
> On Sun, 26 Sep 2004 20:01:04 -0700, Suciu Flavius
> <suciuflavius@tiscali.de> wrote:
>
> > struct timeval start,stop;
> > int elapsed;
> >
> > gettimeofday(&start,NULL);
> >
> > computeWhatIWant();
> >
> > gettimeofday(&stop,NULL);
> >
> >
>
elapsed=(stop.tv_sec-start.tv_sec)*1000000+(stop.tv_usec-start.tv_usec);
> > printf("sprintf: elapsed=%5d
> miliseconds\n",elapsed);
>
> ...or you could use the POSIX difftime function if
> you don't mind
> having a double returned.
>
> Jon.
> -
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next prev parent reply other threads:[~2004-09-27 5:10 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2004-09-26 14:02 Unix Time Ankit Jain
2004-09-27 3:01 ` Suciu Flavius
2004-09-26 22:57 ` Jon Masters
2004-09-27 5:10 ` Ankit Jain [this message]
2004-09-27 10:59 ` szonyi calin
2004-09-27 11:57 ` Jon Masters
2004-09-27 21:33 ` Sumit Narayan
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