From: Justinas <jugu3479@uosis.mif.vu.lt>
To: Jagadeesh Bhaskar P <jbhaskar@hclinsys.com>
Cc: Linux C Programming <linux-c-programming@vger.kernel.org>
Subject: Re: deletion in singly linked list
Date: Tue, 23 Nov 2004 10:42:46 +0200 [thread overview]
Message-ID: <20041123104246.772f55e3@localhost.localdomain> (raw)
In-Reply-To: <1101198249.3786.3.camel@myLinux>
Hello,
i think You can. For instance n is a pointer to curent node and n->next is pointer to next node. lets say we like this tmp = n, and n = n->next. After that free(tmp).
On Tue, 23 Nov 2004 13:54:10 +0530
Jagadeesh Bhaskar P <jbhaskar@hclinsys.com> wrote:
> I am having the address of a single node of a singly linked list. All I
> know about that node is that it is not the head of the list. Now say, I
> want to delete this node. I can infer its next node, but not its
> predicissor. Is there any way to delete that node, without breaking the
> whole linked list down!!
>
> --
> Jagadeesh Bhaskar P <jbhaskar@hclinsys.com>
>
> -
> To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in
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>
next prev parent reply other threads:[~2004-11-23 8:42 UTC|newest]
Thread overview: 21+ messages / expand[flat|nested] mbox.gz Atom feed top
2004-11-23 8:24 deletion in singly linked list Jagadeesh Bhaskar P
2004-11-23 8:42 ` Justinas [this message]
2004-11-23 8:55 ` mikael-aronsson
2004-11-23 9:09 ` Jagadeesh Bhaskar P
2004-11-23 16:57 ` Justinas
2004-11-23 10:08 ` Glynn Clements
2004-11-24 12:43 ` Alphex Kaanoken
2004-11-25 3:49 ` Jagadeesh Bhaskar P
2004-11-25 10:11 ` Alphex Kaanoken
2004-11-25 10:26 ` Jagadeesh Bhaskar P
2004-11-25 11:09 ` Alphex Kaanoken
-- strict thread matches above, loose matches on Subject: below --
2004-11-23 9:00 Bakki Srinivas
2004-11-23 9:13 ` mikael-aronsson
2004-11-23 9:33 ` Jagadeesh Bhaskar P
2004-11-23 9:29 ` Jagadeesh Bhaskar P
2004-11-23 9:59 ` Glynn Clements
2004-11-23 9:35 Bakki Srinivas
2004-11-23 9:55 ` Jagadeesh Bhaskar P
2004-11-23 10:22 Bakki Srinivas
2004-11-23 10:23 Bakki Srinivas
2004-11-23 10:31 Bakki Srinivas
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