From mboxrd@z Thu Jan  1 00:00:00 1970
From: r_zaca <r_zaca@ig.com.br>
Subject: Re: Assignment  make pointers
Date: Mon, 13 Dec 2004 08:04:32 -0200
Message-ID: <20041213_100432_025782.r_zaca@ig.com.br>
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  If you take a look in "man 3 basename", you'll see that basename function 
just returns a pointer to a char. In the case above you need to "cast" the 
pointer returned to be of type int. 
  Like: prog_ptr = (int *) basename (argv[0]); 
  I hope it will help you. 
  Good luck. 


Hello, 

New to the list and to C. Read O'Reilly's Practical C Programming and 
another C book and am now trying to evolve beyond helloworld.c. When I 
compile the snippet below, gcc-3.4.2 on Fedora Core 3 spits out: 
test2.c:11: warning: assignment makes pointer from integer without a 
cast 
test2.c:12: warning: passing arg 1 of `usage' from incompatible pointer 
type 

I just can't figure out why it does that and how to fix it since my 
pointer/casting/C knowledge is definitely lacking. The snippet does work 
ok. Anyone care to enlighten me? 

#include <stdio.h> 

void usage(int *prog_ptr) 
{ 
	fprintf(stdout,"progname is: %s\n",*prog_ptr); 
} 
	 
int main(int argc, char *argv[]) 
{ 
	int *prog_ptr; 
	prog_ptr = basename (argv[0]); 
	usage(&prog_ptr); 
	return(0); 
} 

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