From mboxrd@z Thu Jan  1 00:00:00 1970
From: wwp <subscript@free.fr>
Subject: Re: Function call
Date: Wed, 1 Mar 2006 08:39:13 +0100
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Hello Subbulakshmi,


On Wed, 1 Mar 2006 10:54:03 +0530 "Subbulakshmi Sadagopal (RBIN/EDS2) *" <S=
ubbulakshmi.S@in.bosch.com> wrote:

>=20
> Hello,
>=20
> I have a doubt regarding the following code. There is a void function
> funckey().
>=20
> void funckey()
> {
> ;
> }
>=20
> void main()
> {
> funckey;
> funckey();
> }
>=20
> During execution, the second statement calls the function funckey().
>=20
> What does the compiler do in the first statement funckey?

It evaluates the expression "funckey", which is just a pointer to a function
(as char* foo; is a pointer to char). Function names can be used in some few
situations (passed as parameter to some functions for signal/callback
hooking for instance).


Regards,

--=20
wwp

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