From: Nicolas Kaiser <nikai@nikai.net>
To: Michal Nazarewicz <mina86@mina86.com>
Cc: linux-c-programming@vger.kernel.org
Subject: Re: duplicated modulo
Date: Fri, 1 Apr 2011 12:19:16 +0200 [thread overview]
Message-ID: <20110401121916.34a567da@absol.kitzblitz> (raw)
In-Reply-To: <op.vs86ylxn3l0zgt@mnazarewicz-glaptop>
* "Michal Nazarewicz" <mina86@mina86.com>:
> On Fri, 01 Apr 2011 11:41:13 +0200, Nicolas Kaiser wrote:
> > I'm curious: a duplicated modulo operation can't possibly make
> > any difference, can it?
> >
> > diff -u -p ./arch/powerpc/platforms/powermac/nvram.c
> > /tmp/nothing/arch/powerpc/platforms/powermac/nvram.c
> > --- ./arch/powerpc/platforms/powermac/nvram.c 2011-03-31
> > 09:52:41.674292401 +0200
> > +++ /tmp/nothing/arch/powerpc/platforms/powermac/nvram.c
> > @@ -246,7 +246,6 @@ static u32 core99_calc_adler(u8 *buffer)
> > high = 0;
> > for (cnt=0; cnt<(NVRAM_SIZE-CORE99_ADLER_START); cnt++) {
> > if ((cnt % 5000) == 0) {
> > - high %= 65521UL;
> > high %= 65521UL;
> > }
> > low += buffer[cnt];
>
> It's not just a module. It's also an assignment.
Sure. But I fail to see where between
a %= b;
a %= b;
and
a = (a % b) % b;
and
a %= b;
would be a difference?
Best regards,
Nicolas Kaiser
next prev parent reply other threads:[~2011-04-01 10:19 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-04-01 9:41 duplicated modulo Nicolas Kaiser
2011-04-01 9:50 ` Michal Nazarewicz
2011-04-01 10:19 ` Nicolas Kaiser [this message]
2011-04-01 9:30 ` Bogdan Cristea
2011-04-01 10:28 ` Bastian Bloessl
2011-04-01 11:20 ` Michal Nazarewicz
2011-04-04 8:26 ` Hendrik Visage
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