Re: function pointers in C++

["Darío Mariani" <dmarian@fi.uba.ar>]

Probably what you need is the "pointer to member". It's described in
chapter 15, section 5 in "The C++ Programming Language", from Stroustrup.

elathan@phys.uoa.gr wrote:
> Hello! 
>  
> Suppose I have: 
>  
> class Foo 
> { 
> public: 
> 	Foo(); 
> 	~Foo(); 
> 	int bar(int); 
> }; 
>  
> Now, why I can't do this: 
>  
> Foo *f = new Foo(); 
> taz(f->bar); 
>  
> Where taz()'s protype is: 
>  
> void taz(int (*f)(int)); 
>  
> In plain C, I can do: 
>  
> int f(int) { ... } 
> taz(f); 
>  
> without a problem. Is there a way to accomplish such a thing (i.e. 
> to pass the pointer of a C++ class's member function to another 
> function that expects a pointer to function as an argument)? 
>  
> Regards, 
> --  
> 
> -
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