Re: Dinamic array allocation

[Ron Michael Khu <ronkhu@ntsp.nec.co.jp>]

This is Mr. Fabio's code:

main(int argc, char *argv[])
{
   char *Array[];
   int length,i;
   char foo[10]="bar";
   length = strlen(foo) + atoi(argv[1]);
   Array = malloc(length)
   for(i=;i<length;i++)
       Array[i]="a";
}

Fabio, ur trying to create an array of char ptrs.....
so u  need to modify the way u mallocs space...
   Array = malloc(length)
is only applicable if u have defined Array
as char *Array;

(and u need to initialize "i" just in case... im not
sure about the default value of ints)



Lejanson C. Go wrote:

> I hope i am correct. :D
>
> ptr = (char *) malloc (strtol(argv[1])+strlen(foo));
>
>
> Ron Michael Khu wrote:
>
>> arvp[1] is string....
>> u should convert it to a numeric type via atoi() or strtol()....
>>
>> =)
>>
>> Fabio wrote:
>>
>>> Hi.
>>>
>>> I am programming a C code that gets argv[1] as the lenght of an 
>>> array that is the copy of an array plus more data.
>>>
>>> So, the appication runs as: ./a.out 100
>>>
>>> It create an array of 100 bytes and adds a static defined array plus 
>>> more data, like:
>>>
>>> char *foo[5]="bar"
>>> main(int argc, char *argv[])
>>> {
>>>    char *Ptr[];
>>>    Ptr = malloc( argv[1]+strlen(foo));
>>>    ....
>>> }
>>>
>>> Makes sense? guess no.
>>>
>>> Any suggestion is welcome.
>>>
>>> thanks in advance
>>> -
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>>
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>
>
>