Re: data structure question

[gumbold <gumbold@bonbon.net>]

Glynn Clements wrote:

>gumbold wrote:
>
>  
>
>>So char abc[0] actualy pointer to chat?
>>    
>>
>
>No, it's an array of char.
>
>  
>
>>It should be 4 byte long on x86. I can't see it with sizeof.
>>    
>>
>
>It's zero bytes long.
>
>If you had:
>
>	struct abc {
>	    __u16 a;
>	    __u16 b;
>	    char abc[4];
>	};
>
>then sizeof(struct abc) would be 8 and the offset of abc from the
>beginning of the structure would be 4.
>
>With:
>
>	struct abc {
>	    __u16 a;
>	    __u16 b;
>	    char abc[0];
>	};
>
>sizeof(struct abc) would be 4 and the offset of abc from the beginning
>of the structure would still be 4 (i.e. p->abc refers to the first
>byte after the structure).
>
>  
>
I understand. But if you doing `p->abc = (char *)malloc(111)' so you 
copy 4 bytes to the place
started from p->abc, but it is out of struct abc memory (it is only 4 
byte). Should be error?