From: James Colannino <james@colannino.org>
To: linux-c-programming@vger.kernel.org
Subject: Using realloc()
Date: Fri, 10 Jun 2005 23:07:33 -0700 [thread overview]
Message-ID: <42AA7FA5.4040806@colannino.org> (raw)
Hey everyone. I have a question about realloc(). I was hoping to use
realloc() to allocate more memory to an already existing string, but the
problem was, I didn't know if the original information would stay intact
or not after running realloc(). I wrote the following program to test this:
#include <stdio.h>
int main() {
char *string;
size_t size = sizeof(char);
string = (char *)malloc(size);
string[0] = 'a';
string[1] = '\0';
printf ("Before realloc(): %p: %s\nsize: %d\n", string, string, size);
size = size * 5;
string = (char *)realloc(string, size);
printf ("After realloc(): %p: %s\nsize: %d\n", string, string, size);
return 0;
}
The string data stays the same after running realloc(), so at least in
this circumstance it worked like I had hoped. However, when printing
the pointer to the screen, I saw that it didn't change, and I know that
sometimes realloc() needs to start at a new address in memory which
means the pointer changes, so my question is, will the original data
stay intact if this happens?
Thanks in advance :)
James
--
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My homepage: http://james.colannino.org/
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next reply other threads:[~2005-06-11 6:07 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2005-06-11 6:07 James Colannino [this message]
2005-06-11 8:08 ` Using realloc() Steve Graegert
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