Re: Some question about one method.

[Jeff Woods <Kazrak+kernel@cesmail.net>]

At 5/25/2004 01:24 AM +0200, Charlie Gordon wrote:
>>char *a;
>>short *b;
>>int *c;
>>long *d;
>>long long *e;
>>
>>--> What's the difference between a++ and e++?
>
>it makes them point to the next element in the arrays of respective types, 
>and as such increments the binary value by a different amount.
>
>More interestingly what is the difference between e[5] and 5[e] ?

Since pointer addition is commutative [i.e., *(e+5) == *(5+e) ] they're the 
same thing.

My favorite C obfuscation.  (And I only use it when I intend to be obtuse! 
:)  Note below that "j" is an int and "t" is an array of char and there's a 
"putchar(j[t])" in there.  [Yes, it compiles and runs.]

--
int main(void){int j=2003;/*(c)2003 cishikawa.*/
char t[]="+<WJ> @abcdefghijklmnopqrstuvwxyz.,\n\"";
char*i="y>b<+x,m+tie@.juswndnc@dt<Wupi\"JWhysbJirviiy";
while(*i)((j+=strchr(t,*i++)-(int)t),(j%=sizeof t-1),
(putchar(j[t])));return 0;}/* under GPL */