* Re: Variable to sizeof function.
2005-07-16 6:44 ` Vikas S
@ 2005-07-16 7:04 ` Steve Graegert
2005-07-16 8:26 ` Steven Smith
` (2 subsequent siblings)
3 siblings, 0 replies; 13+ messages in thread
From: Steve Graegert @ 2005-07-16 7:04 UTC (permalink / raw)
To: Vikas S; +Cc: Rechberger Markus, linux-c-programming
On 7/16/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
>
> Thanks, This is a workable solution.
> But the issue is I've some 100+ structures. So, writing
> a if or case is going to be difficult.
Wow, that's a lot of work :-)
> a) You are right.
> b) Yes. I want to pass a structure name. ie, make sizeof
> accept a variable.
>
> Is this impossible?
I guess you want to save typing and be able to query the size of a
particular structure dynamically simply by specifying its name (the
variable name) on the command line. Unfortunately there is no
mechanism known to me that allows it. The C programming language
provides no way to do some name to variable mapping. A couple of days
ago, one has asked how to obtain the number and names of function
arguments dynamically which is a problem of the same kind. What you
are looking for is some kind of reflection to fetch type information
at run-time.
You can try to set up a table with pointers to every structure and use
this entry to query the size. I don't see another solution.
Regards
\Steve
> Thanks,
> Vikas
>
> --- Steve Graegert <graegerts@gmail.com> wrote:
>
> > On 7/15/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
> > >
> > > I guess I was not clear. Say, we have two structures.
> > >
> > > str1 {int x, char y} and str2 {int x, char *y};
> >
> > OK...
> >
> > > printf(sizeof(struct str1)); will give proper output. ie memory occupied
> > > by str1.
> >
> > ...reasonable...
> >
> > > What I want is, instead of hard-coding str1 etc., I want to find
> > > the size of structure which I will give as 1st argument. So, if the
> > > program name is size, i'll give:
> > > $ ./size str1 --- to get size of str1
> > > $ ./size str2 --- to get size of str2
> >
> > This makes things even more confusing to me. So, you want
> >
> > (a) query the size of a particular structure among others
> > (b) provide a structure as an argument to your program
> >
> > identified by name? Obviously (b) is something completely impossible,
> > obscure at least. The solution to (a) is simple:
> >
> > struct s1 { int i; char *c; } str1;
> > struct s2 { int i; char c[5]; } str2;
> >
> > if (argc != 2) return 0;
> >
> > if (!strcmp(argv[1], "str1"))
> > printf("sizeof(str1): %d\n", sizeof(str1));
> > else
> > printf("sizeof(str2): %d\n", sizeof(str2))
> >
> > $ cc -o test test.c
> >
> > $ ./test str2
> > sizeof(str2): 12
> >
> >
> > > The code which I gave earlier is giving compile-time error message.
> > >
> > > Thanks,
> > > Vikas
> > > --- Rechberger Markus <mrechberger@gmail.com> wrote:
> > >
> > > > strlen on a null pointer will segfault...
> > > > if arc is 1 then argv[0] will contain a pointer to an array of char
> > > > if arc is 2 then argv[1] (the users first argument) will contain an
> > > > array of char..
> > > > so don't forget to check the number of arguments ..
> > > >
> > > > On 7/15/05, Vadiraj <vadiraj.cs@gmail.com> wrote:
> > > > > Vikas,
> > > > >
> > > > > On 7/15/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
> > > > > > I want to find out the size of a structure which the user will give as an argument
> > > > > > as follows.
> > > > > >
> > > > > > #include <> -- All includes..
> > > > > > ..
> > > > > > main(int arc, char *argv[])
> > > > >
> > > > > argv is a charecter pointer . You cannot pass struct * as an
> > > > > arguement to main.
> > > > >
> > > > > > {
> > > > > > printf("Size of structure %s is: %d\n", argv[1], sizeof(struct argv[1]));
> > > > >
> > > > > use strlen(argv[1]) to find the lenght of the string.
> > > > >
> > > > > --
> > > > > cheers,
> > > > > Vadi
> > > > > -
> > > > > To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in
> > > > > the body of a message to majordomo@vger.kernel.org
> > > > > More majordomo info at http://vger.kernel.org/majordomo-info.html
> > > > >
> > > > -
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> > > >
> > >
> > >
> > >
> > >
> > >
> > > __________________________________
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> >
> >
> > --
> > ______________________________________
> > Steve Graegert //
> > Software Consultancy // Whether you know it or not, if you
> > Mobile: +49 (176) 21248869 // are a hacker, you are a revolutionary.
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> >
>
>
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______________________________________
Steve Graegert //
Software Consultancy // Whether you know it or not, if you
Mobile: +49 (176) 21248869 // are a hacker, you are a revolutionary.
Office: +49 (9131) 7126409 // Don't worry, you're on the right side.
____________________________// -- Dr Crash / Phrack 6 / phile 3
^ permalink raw reply [flat|nested] 13+ messages in thread* Re: Variable to sizeof function.
2005-07-16 6:44 ` Vikas S
2005-07-16 7:04 ` Steve Graegert
@ 2005-07-16 8:26 ` Steven Smith
2005-07-16 14:30 ` Eric Bambach
2005-07-17 16:27 ` Vadiraj
3 siblings, 0 replies; 13+ messages in thread
From: Steven Smith @ 2005-07-16 8:26 UTC (permalink / raw)
To: Vikas S; +Cc: Steve Graegert, Rechberger Markus, linux-c-programming, sos22
[-- Attachment #1: Type: text/plain, Size: 691 bytes --]
> Thanks, This is a workable solution.
> But the issue is I've some 100+ structures. So, writing
> a if or case is going to be difficult.
>
> b) Yes. I want to pass a structure name. ie, make sizeof
> accept a variable.
You can't do this in C, but you might be able to achieve something
similar using gdb, if performance isn't important. If your
application is compiled with debug symbols, you can go ``inspect
sizeof(struct my_struct)'' from the gdb prompt, and get the number
you're looking for; you may be able to automate this.
If your application doesn't have debug symbols, then the information
you need isn't preserved by the compiler, so you're stuffed.
Steven.
[-- Attachment #2: Digital signature --]
[-- Type: application/pgp-signature, Size: 189 bytes --]
^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: Variable to sizeof function.
2005-07-16 6:44 ` Vikas S
2005-07-16 7:04 ` Steve Graegert
2005-07-16 8:26 ` Steven Smith
@ 2005-07-16 14:30 ` Eric Bambach
2005-07-17 16:27 ` Vadiraj
3 siblings, 0 replies; 13+ messages in thread
From: Eric Bambach @ 2005-07-16 14:30 UTC (permalink / raw)
To: Vikas S; +Cc: linux-c-programming
Vika,
Perhaps you can add a sizeof field to your structures and query it?
struct s{
int a;
float b;
int mysize = sizeof(s);
};
int function(struct *s){
return s->mysize;
}
Pardon my code, its more like psuedocode than anything that will compile, but
the idea is there. The problem is if you have pointers to strings in your
struct, then it won't get the size properly at run-time, but if they're all
static elements, it may work.
On Saturday 16 July 2005 01:44 am, Vikas S wrote:
> Thanks, This is a workable solution.
> But the issue is I've some 100+ structures. So, writing
> a if or case is going to be difficult.
>
> a) You are right.
> b) Yes. I want to pass a structure name. ie, make sizeof
> accept a variable.
>
> Is this impossible?
>
> Thanks,
> Vikas
>
> --- Steve Graegert <graegerts@gmail.com> wrote:
> > On 7/15/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
> > > I guess I was not clear. Say, we have two structures.
> > >
> > > str1 {int x, char y} and str2 {int x, char *y};
> >
> > OK...
> >
> > > printf(sizeof(struct str1)); will give proper output. ie memory
> > > occupied by str1.
> >
> > ...reasonable...
> >
> > > What I want is, instead of hard-coding str1 etc., I want to find
> > > the size of structure which I will give as 1st argument. So, if the
> > > program name is size, i'll give:
> > > $ ./size str1 --- to get size of str1
> > > $ ./size str2 --- to get size of str2
> >
> > This makes things even more confusing to me. So, you want
> >
> > (a) query the size of a particular structure among others
> > (b) provide a structure as an argument to your program
> >
> > identified by name? Obviously (b) is something completely impossible,
> > obscure at least. The solution to (a) is simple:
> >
> > struct s1 { int i; char *c; } str1;
> > struct s2 { int i; char c[5]; } str2;
> >
> > if (argc != 2) return 0;
> >
> > if (!strcmp(argv[1], "str1"))
> > printf("sizeof(str1): %d\n", sizeof(str1));
> > else
> > printf("sizeof(str2): %d\n", sizeof(str2))
> >
> > $ cc -o test test.c
> >
> > $ ./test str2
> > sizeof(str2): 12
> >
> > > The code which I gave earlier is giving compile-time error message.
> > >
> > > Thanks,
> > > Vikas
> > >
> > > --- Rechberger Markus <mrechberger@gmail.com> wrote:
> > > > strlen on a null pointer will segfault...
> > > > if arc is 1 then argv[0] will contain a pointer to an array of char
> > > > if arc is 2 then argv[1] (the users first argument) will contain an
> > > > array of char..
> > > > so don't forget to check the number of arguments ..
> > > >
> > > > On 7/15/05, Vadiraj <vadiraj.cs@gmail.com> wrote:
> > > > > Vikas,
> > > > >
> > > > > On 7/15/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
> > > > > > I want to find out the size of a structure which the user will
> > > > > > give as an argument as follows.
> > > > > >
> > > > > > #include <> -- All includes..
> > > > > > ..
> > > > > > main(int arc, char *argv[])
> > > > >
> > > > > argv is a charecter pointer . You cannot pass struct * as an
> > > > > arguement to main.
> > > > >
> > > > > > {
> > > > > > printf("Size of structure %s is: %d\n", argv[1], sizeof(struct
> > > > > > argv[1]));
> > > > >
> > > > > use strlen(argv[1]) to find the lenght of the string.
> > > > >
> > > > > --
> > > > > cheers,
> > > > > Vadi
> > > > > -
> > > > > To unsubscribe from this list: send the line "unsubscribe
> > > > > linux-c-programming" in the body of a message to
> > > > > majordomo@vger.kernel.org
> > > > > More majordomo info at http://vger.kernel.org/majordomo-info.html
> > > >
> > > > -
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> > >
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> >
> > --
> > ______________________________________
> > Steve Graegert //
> > Software Consultancy // Whether you know it or not, if you
> > Mobile: +49 (176) 21248869 // are a hacker, you are a revolutionary.
> > Office: +49 (9131) 7126409 // Don't worry, you're on the right side.
> > ____________________________// -- Dr Crash / Phrack 6 / phile 3
> > -
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>
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----------------------------------------
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> All is fine except that I can reliably "oops" it simply by trying to read
> from /proc/apm (e.g. cat /proc/apm).
> oops output and ksymoops-2.3.4 output is attached.
> Is there anything else I can contribute?
The latitude and longtitude of the bios writers current position, and
a ballistic missile.
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^ permalink raw reply [flat|nested] 13+ messages in thread* Re: Variable to sizeof function.
2005-07-16 6:44 ` Vikas S
` (2 preceding siblings ...)
2005-07-16 14:30 ` Eric Bambach
@ 2005-07-17 16:27 ` Vadiraj
2005-08-01 6:10 ` Query in C avinash pawar
3 siblings, 1 reply; 13+ messages in thread
From: Vadiraj @ 2005-07-17 16:27 UTC (permalink / raw)
To: Vikas S; +Cc: Steve Graegert, Rechberger Markus, linux-c-programming
On 7/16/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
>
> Thanks, This is a workable solution.
> But the issue is I've some 100+ structures. So, writing
> a if or case is going to be difficult.
Another way I can suggest would be passing the file name at command prompt.
./size foo.txt
foo.txt should contain 100+ structure names.
read the file contents and follow steve's suggestion.
>
> a) You are right.
> b) Yes. I want to pass a structure name. ie, make sizeof
> accept a variable.
>
> Is this impossible?
>
> Thanks,
> Vikas
>
> --- Steve Graegert <graegerts@gmail.com> wrote:
>
> > On 7/15/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
> > >
> > > I guess I was not clear. Say, we have two structures.
> > >
> > > str1 {int x, char y} and str2 {int x, char *y};
> >
> > OK...
> >
> > > printf(sizeof(struct str1)); will give proper output. ie memory occupied
> > > by str1.
> >
> > ...reasonable...
> >
> > > What I want is, instead of hard-coding str1 etc., I want to find
> > > the size of structure which I will give as 1st argument. So, if the
> > > program name is size, i'll give:
> > > $ ./size str1 --- to get size of str1
> > > $ ./size str2 --- to get size of str2
> >
> > This makes things even more confusing to me. So, you want
> >
> > (a) query the size of a particular structure among others
> > (b) provide a structure as an argument to your program
> >
> > identified by name? Obviously (b) is something completely impossible,
> > obscure at least. The solution to (a) is simple:
> >
> > struct s1 { int i; char *c; } str1;
> > struct s2 { int i; char c[5]; } str2;
> >
> > if (argc != 2) return 0;
> >
> > if (!strcmp(argv[1], "str1"))
> > printf("sizeof(str1): %d\n", sizeof(str1));
> > else
> > printf("sizeof(str2): %d\n", sizeof(str2))
> >
> > $ cc -o test test.c
> >
> > $ ./test str2
> > sizeof(str2): 12
> >
> >
> > > The code which I gave earlier is giving compile-time error message.
> > >
> > > Thanks,
> > > Vikas
> > > --- Rechberger Markus <mrechberger@gmail.com> wrote:
> > >
> > > > strlen on a null pointer will segfault...
> > > > if arc is 1 then argv[0] will contain a pointer to an array of char
> > > > if arc is 2 then argv[1] (the users first argument) will contain an
> > > > array of char..
> > > > so don't forget to check the number of arguments ..
> > > >
> > > > On 7/15/05, Vadiraj <vadiraj.cs@gmail.com> wrote:
> > > > > Vikas,
> > > > >
> > > > > On 7/15/05, Vikas S <vikas_soolapani@yahoo.com> wrote:
> > > > > > I want to find out the size of a structure which the user will give as an argument
> > > > > > as follows.
> > > > > >
> > > > > > #include <> -- All includes..
> > > > > > ..
> > > > > > main(int arc, char *argv[])
> > > > >
> > > > > argv is a charecter pointer . You cannot pass struct * as an
> > > > > arguement to main.
> > > > >
> > > > > > {
> > > > > > printf("Size of structure %s is: %d\n", argv[1], sizeof(struct argv[1]));
> > > > >
> > > > > use strlen(argv[1]) to find the lenght of the string.
> > > > >
> > > > > --
> > > > > cheers,
> > > > > Vadi
> > > > > -
> > > > > To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in
> > > > > the body of a message to majordomo@vger.kernel.org
> > > > > More majordomo info at http://vger.kernel.org/majordomo-info.html
> > > > >
> > > > -
> > > > To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in
> > > > the body of a message to majordomo@vger.kernel.org
> > > > More majordomo info at http://vger.kernel.org/majordomo-info.html
> > > >
> > >
> > >
> > >
> > >
> > >
> > > __________________________________
> > > Do you Yahoo!?
> > > Yahoo! Mail - You care about security. So do we.
> > > http://promotions.yahoo.com/new_mail
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> > >
> >
> >
> > --
> > ______________________________________
> > Steve Graegert //
> > Software Consultancy // Whether you know it or not, if you
> > Mobile: +49 (176) 21248869 // are a hacker, you are a revolutionary.
> > Office: +49 (9131) 7126409 // Don't worry, you're on the right side.
> > ____________________________// -- Dr Crash / Phrack 6 / phile 3
> > -
> > To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in
> > the body of a message to majordomo@vger.kernel.org
> > More majordomo info at http://vger.kernel.org/majordomo-info.html
> >
>
>
> __________________________________________________
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>
--
cheers,
Vadi
^ permalink raw reply [flat|nested] 13+ messages in thread* Query in C
2005-07-17 16:27 ` Vadiraj
@ 2005-08-01 6:10 ` avinash pawar
2005-08-01 6:44 ` Steve Graegert
0 siblings, 1 reply; 13+ messages in thread
From: avinash pawar @ 2005-08-01 6:10 UTC (permalink / raw)
To: Vadiraj; +Cc: Vikas S, Steve Graegert, Rechberger Markus, linux-c-programming
Hello Everyone ,
Can anyone of you please tell me..
what does extern "C" int func(int *,foo) accomplish ?
waiting for your reply.
regards,
Avinash
^ permalink raw reply [flat|nested] 13+ messages in thread* Re: Query in C
2005-08-01 6:10 ` Query in C avinash pawar
@ 2005-08-01 6:44 ` Steve Graegert
0 siblings, 0 replies; 13+ messages in thread
From: Steve Graegert @ 2005-08-01 6:44 UTC (permalink / raw)
To: avinash pawar; +Cc: linux-c-programming
On 8/1/05, avinash pawar <lkmails@gmail.com> wrote:
> Hello Everyone ,
>
> Can anyone of you please tell me..
>
> what does extern "C" int func(int *,foo) accomplish ?
>
When using existing C headers that already conform to ANSI C in C++
they need to be slightly modified to enable proper linkage for the
language and to ensure that C++ keywords are not used as identifiers.
This means that you can use C headers in C++ projects in the following way:
#ifdef __cplusplus
extern "C" {
#endif
...
int func(int *,foo);
...
#ifdef __cplusplus
}
#endif
Code placed between the two ifdefs is either linked as C or C++. The
__cplusplus macro is usually predefined in appropriate system headers.
To answer your question: when a routine will be called from another
language (here C is called from C++) it should be declared in C++ as
extern "C" int func(int *,foo);
The extern "C" causes the routine to have a so called 'unmangled' name
that can be refered to not only from C but also from Fortran or Cobol.
Without extern "C" the routine will get a link 'mangled' link name
like func__abc.
Regards
\Steve
--
Steve Graegert
Software Consultancy
Mobile: +49 (176) 21248869
Office: +49 (9131) 7126409
^ permalink raw reply [flat|nested] 13+ messages in thread