Re: execv fails with EFAULT

["Steve Graegert" <graegerts@gmail.com>]

On 3/7/07, Prasanta Sadhukhan <Prasanta.Sadhukhan@sun.com> wrote:
> Hi,
>
> When I tried the following program
> void test4()
> {
>     printf("doing execv\n");
>     if(execv("/bin/ls", "-l") == -1)
>         printf("exec failed with errno %d\n", errno);
>     else
>         printf("exec succeed\n");
> }

Prasanta,

A NULL terminated array of arguments must be passed to execv(2) as the
prototype indicates: int execv(const char *path, char *const argv[]);

For example:

#include <unistd.h>

char *cmd[] = { "ls", "-l", NULL };
int result = execv ("/bin/ls", cmd);

An error of EFAULT usually means that an argument points to an illegal address.

	\Steve

--

Steve Grägert <steve@graegert.com>
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