Re: What means "\xc7\x44\x24\x18\xda\xff\xff\xff\xe8" ?

[Niklaus <niklaus@gmail.com>]

On 4/5/06, Glynn Clements <glynn@gclements.plus.com> wrote:
>
> openbsd shen wrote:
>
> > In a get_sct() function, it have some lines:
> >
> > pt = (char *) memmem(p+7, SCLEN-(p-code)-7,
> > "\xc7\x44\x24\x18\xda\xff\xff\xff\xe8", 9);
> > if (!pt)
> >      return 0;
> >
> >
> > when run here, it always return 0, so I want to know what means the
> > "\xc7\x44\x24\x18\xda\xff\xff\xff\xe8" ?
>
> It's just the string of bytes being searched for, specified as a C
> string literal using hexadecimal codes.
Since the characters are not printable he has given it the values of
ascii characters in hexadecimal. It always returns NULL , maybe
because the text you are running it on doesn't have that string. Try
running it on the string containing ÇD$Úÿÿÿè
It will not return NULL.

Just look into man memmem

#include<stdio.h>
#include<string.h>

#include<stdio.h>

int main()
{
                char *s="\xc7\x44\x24\x18\xda\xff\xff\xff\xe8";
                char *s1="\x4e\x49\x4b";
                char s2[]="Niklaus";
                char s3[]="IINIKlaus";
                char s4[]="HiÇD$ÚÿÿÿèHiya";
                printf("%s\n",s);
                printf("%s\n",s1);
                printf("%s\n", memmem(s2,sizeof(s2),s1,3));
                printf("%s\n", memmem(s3,sizeof(s3),s1,3));
                printf("%s\n", memmem(s4,sizeof(s4),s,3));
                return 0;
}

~

>
> --
> Glynn Clements <glynn@gclements.plus.com>
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