From mboxrd@z Thu Jan 1 00:00:00 1970 From: Linus Walleij Subject: Re: [PATCH v2 05/11] pinctrl: mediatek: avoid virtual gpio trying to set reg Date: Fri, 23 Aug 2019 10:57:03 +0200 Message-ID: References: <1566206502-4347-1-git-send-email-mars.cheng@mediatek.com> <1566206502-4347-6-git-send-email-mars.cheng@mediatek.com> Mime-Version: 1.0 Content-Type: text/plain; charset="UTF-8" Return-path: In-Reply-To: <1566206502-4347-6-git-send-email-mars.cheng@mediatek.com> Sender: linux-kernel-owner@vger.kernel.org To: Mars Cheng Cc: Matthias Brugger , Rob Herring , Marc Zyngier , Stephen Boyd , Sean Wang , CC Hwang , Loda Chou , "linux-kernel@vger.kernel.org" , "moderated list:ARM/Mediatek SoC support" , "open list:OPEN FIRMWARE AND FLATTENED DEVICE TREE BINDINGS" , wsd_upstream@mediatek.com, mtk01761 , linux-clk List-Id: devicetree@vger.kernel.org On Mon, Aug 19, 2019 at 11:22 AM Mars Cheng wrote: > for virtual gpios, they should not do reg setting and > should behave as expected for eint function. > > Signed-off-by: Mars Cheng This does not explain what a "virtual GPIO" is in this context, so please elaborate. What is this? Why does it exist? What is it used for? GPIO is "general purpose input/output" and it is a pretty rubbery category already as it is, so we need to define our terms pretty strictly. > +bool mtk_is_virt_gpio(struct mtk_pinctrl *hw, unsigned int gpio_n) > +{ > + const struct mtk_pin_desc *desc; > + bool virt_gpio = false; > + > + if (gpio_n >= hw->soc->npins) > + return virt_gpio; > + > + desc = (const struct mtk_pin_desc *)&hw->soc->pins[gpio_n]; > + > + if (desc->funcs && > + desc->funcs[desc->eint.eint_m].name == 0) NULL check is done like this: if (desc->funcs && !desc->funcs[desc->eint.eint_m].name) > + virt_gpio = true; So why is this GPIO "virtual" because it does not have a name in the funcs table? > @@ -278,6 +295,9 @@ static int mtk_xt_set_gpio_as_eint(void *data, unsigned long eint_n) > if (err) > return err; > > + if (mtk_is_virt_gpio(hw, gpio_n)) > + return 0; So does this mean we always succeed in setting a GPIO as eint if it is virtual? Why? Explanatory comment is needed. > @@ -693,6 +693,9 @@ static int mtk_gpio_get_direction(struct gpio_chip *chip, unsigned int gpio) > const struct mtk_pin_desc *desc; > int value, err; > > + if (mtk_is_virt_gpio(hw, gpio)) > + return 1; Why are "virtual GPIOs" always inputs? Yours, Linus Walleij