Re: [PATCH v3 2/3] tracing/probes: Fix BTF kflag check for anonymous struct member access

[Masami Hiramatsu (Google) <mhiramat@kernel.org>]

On Tue, 1 Sep 2026 10:37:25 -0400
Steven Rostedt <rostedt@goodmis.org> wrote:

> On Tue,  1 Sep 2026 23:21:49 +0900
> "Masami Hiramatsu (Google)" <mhiramat@kernel.org> wrote:
> 
> > From: Masami Hiramatsu (Google) <mhiramat@kernel.org>
> > 
> > btf_find_struct_member() traverses into nested anonymous structures and
> > unions to find a struct member. However, get_bitoffset_of_field() in
> > trace_probe.c checked btf_type_kflag(type) using the outer parent type
> > instead of the actual anonymous structure/union that directly contains
> > the found member.
> > 
> > If the parent structure and anonymous structure have mismatched kflags
> > (e.g., the parent has kflag=0 while the anonymous structure has kflag=1
> > because it contains bitfields), the bitfield size encoded in the upper
> > 8 bits of member->offset is erroneously treated as part of the byte/bit
> > offset, corrupting the resolved offset and failing to set last_bitsize.
> > Similarly, btf_find_struct_member() pushed anonymous member offsets
> > onto anon_stack without masking BTF_MEMBER_BIT_OFFSET() when kflag is set.
> > 
> > To fix this problem, update btf_find_struct_member() to return actual
> > containing structure/union type via member_type, use appropriate
> > __btf_member_bit_offset() to get bit offset, and use member_type for
> > btf_type_kflag() in get_bitoffset_of_field().
> > 
> > Fixes: c440adfbe302 ("tracing/probes: Support BTF based data structure field access")
> > Cc: stable@vger.kernel.org
> > Reported-by: Sashiko <sashiko-bot@kernel.org>
> > Closes: https://lore.kernel.org/all/20260822095110.0772E1F000E9@smtp.kernel.org/
> > Assisted-by: Antigravity:gemini-3.7-flash
> > Signed-off-by: Masami Hiramatsu (Google) <mhiramat@kernel.org>
> 
> Reviewed-by: Steven Rostedt <rostedt@goodmis.org>

Thanks! Let me pick those to probes/fixes.


> 
> -- Steve


-- 
Masami Hiramatsu (Google) <mhiramat@kernel.org>