From: Jan Kara <jack@suse.cz>
To: Tao Ma <tm@tao.ma>
Cc: linux-ext4@vger.kernel.org, Jan Kara <jack@suse.cz>,
Lukas Czerner <lczerner@redhat.com>
Subject: Re: [PATCH v2] ext3: speed up group trim with the right free block count.
Date: Fri, 21 Jan 2011 16:02:06 +0100 [thread overview]
Message-ID: <20110121150206.GE5302@quack.suse.cz> (raw)
In-Reply-To: <1295619576-5662-1-git-send-email-tm@tao.ma>
On Fri 21-01-11 22:19:36, Tao Ma wrote:
> On 01/21/2011 06:44 PM, Lukas Czerner wrote:
> > Nice catch, do you plan to do the same for ext4 ? Btw, I do not think
> > there is a need for new variable (free_count), you can as well do :
> >
> > free_blocks -= next - start;
> > ...
> > if (free_blocks < minblocks)
> > break;
> yeah, the extra varaible isn't needed. Here is the updated patch.
>
> Regards,
> Tao
>
> Subject: [PATCH v2] ext3: speed up group trim with the right free block count.
> From 48ab7651409df9b21dfaa9cec6a8db62467b8ca7 Mon Sep 17 00:00:00 2001
> From: Tao Ma <boyu.mt@taobao.com>
> Date: Fri, 21 Jan 2011 22:09:20 +0800
> Subject: [PATCH v2] ext3: speed up group trim with the right free block count.
>
> When we trim some free blocks in a group of ext3, we should
> calculate the free blocks properly and check whether there are
> enough freed blocks left for us to trim. Current solution will
> only calculate free spaces if they are large for a trim which
> is wrong.
>
> Let us see a small example:
> a group has 1.5M free which are 300k, 300k, 300k, 300k, 300k.
> And minblocks is 1M. With current solution, we have to iterate
> the whole group since these 300k will never be subtracted from
> 1.5M. But actually we should exit after we find the first 2
> free spaces since the left 3 chunks only sum up to 900K if we
> subtract the first 600K although they can't be trimed.
Thanks. Merged.
Honza
>
> Cc: Jan Kara <jack@suse.cz>
> Cc: Lukas Czerner <lczerner@redhat.com>
> Signed-off-by: Tao Ma <boyu.mt@taobao.com>
> ---
> fs/ext3/balloc.c | 3 ++-
> 1 files changed, 2 insertions(+), 1 deletions(-)
>
> diff --git a/fs/ext3/balloc.c b/fs/ext3/balloc.c
> index 045995c..b9697f7 100644
> --- a/fs/ext3/balloc.c
> +++ b/fs/ext3/balloc.c
> @@ -1991,6 +1991,7 @@ ext3_grpblk_t ext3_trim_all_free(struct super_block *sb, unsigned int group,
> spin_unlock(sb_bgl_lock(sbi, group));
> percpu_counter_sub(&sbi->s_freeblocks_counter, next - start);
>
> + free_blocks -= next - start;
> /* Do not issue a TRIM on extents smaller than minblocks */
> if ((next - start) < minblocks)
> goto free_extent;
> @@ -2040,7 +2041,7 @@ free_extent:
> cond_resched();
>
> /* No more suitable extents */
> - if ((free_blocks - count) < minblocks)
> + if (free_blocks < minblocks)
> break;
> }
>
> --
> 1.7.1
>
--
Jan Kara <jack@suse.cz>
SUSE Labs, CR
prev parent reply other threads:[~2011-01-21 15:02 UTC|newest]
Thread overview: 4+ messages / expand[flat|nested] mbox.gz Atom feed top
2011-01-21 1:59 [PATCH] ext3: speed up group trim with the right free block count Tao Ma
2011-01-21 10:44 ` Lukas Czerner
2011-01-21 14:19 ` [PATCH v2] " Tao Ma
2011-01-21 15:02 ` Jan Kara [this message]
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
Avoid top-posting and favor interleaved quoting:
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style
* Reply using the --to, --cc, and --in-reply-to
switches of git-send-email(1):
git send-email \
--in-reply-to=20110121150206.GE5302@quack.suse.cz \
--to=jack@suse.cz \
--cc=lczerner@redhat.com \
--cc=linux-ext4@vger.kernel.org \
--cc=tm@tao.ma \
/path/to/YOUR_REPLY
https://kernel.org/pub/software/scm/git/docs/git-send-email.html
* If your mail client supports setting the In-Reply-To header
via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line
before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox;
as well as URLs for NNTP newsgroup(s).