Re: fbmem: is bootup logo broken for monochrome LCD ?

["Franck Bui-Huu" <vagabon.xyz@gmail.com>]

On 11/20/06, James Simmons <jsimmons@infradead.org> wrote:
>
> > On 11/17/06, James Simmons <jsimmons@infradead.org> wrote:
> > >
> > > Are those actually numbers? If they are the problem isn't byte reversal
> > > but bit shifting.
> > >
> > > 1010100 = 54
> > > 0101010 = 2A
> >
> > It's not byte reversal, but _bits_ of each bytes have been inversed
> > (bit7->bit0, bit6->bit1, bit5->bit2, bit4->bit3, bit3->bit4, ...)
> > after calling slow_imageblit(). Is it something expected ?
>
> Yipes!! Bit reversal. I have never seen that before. Is only the logo
> messed up? Slow_imageblit can be called if there is no dword alignment
> for the font bitmaps. So the question is do most if not all our fonts
> look okay?
>

No, it's not an only logo issue. Bit reversals happen for all images
which are passed to slow_imageblit() including all fonts.

Can it be a 'bit_per_pixel = 1' issue ? It seems that this config has
not been widely tested.

If you look at slow_imageblit() current implementation and for example
let's say that at the begining of the function we have:

	- __LITTLE_ENDIAN is defined
	- bpp = 1
	- fgcolor = 1
	- bgcolor = 0
	- start_index = 0

The function core can be simplified into:

	for (i = image->height; i--; ) {
		shift = val = 0;
		l = 8;
		j = image->width;
		dst = (u32 __iomem *) dst1;
		s = src;

		while (j--) {
			l--;
			color = (*s & (1 << l)) ? 1 : 0;
			val |= color << shift;
			
			/* Did the bitshift spill bits to the next long? */
			if (shift >= null_bits) {
				FB_WRITEL(val, dst++);
				val = (shift == null_bits) ? 0 :
					FB_SHIFT_LOW(color,32 - shift);
			}
			shift += 1;
			shift &= (32 - 1);
			if (!l) { l = 8; s++; };
		}

		[ ...]

Doesn't this bit of code do a bit reversal ? Specially these 2
following lines of code:

	color = (*s & (1 << l)) ? 1 : 0;
	val |= color << shift;


with 'l' taking values from 7 to 0, and 'shift' taking values from 0
to 31.

Thanks
		Franck

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