Re: [PATCH 12/13] Make generic_make_request handle arbitrarily large bios

[NeilBrown <neilb@suse.de>]

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Hi Kent,
 there is lots of good stuff in this series and I certainly hope a lot of it
 can eventually go upstream.

 However there is a part of this patch that I don't think is safe:


> +static void __bio_submit_split(struct closure *cl)
> +{
> +	struct bio_split_hook *s = container_of(cl, struct bio_split_hook, cl);
> +	struct bio *bio = s->bio, *n;
> +
> +	do {
> +		n = bio_split(bio, bio_max_sectors(bio),
> +			      GFP_NOIO, s->q->bio_split);
> +		if (!n)
> +			continue_at(cl, __bio_submit_split, bio_split_wq);
> +
> +		closure_get(cl);
> +		generic_make_request(n);
> +	} while (n != bio);
> +
> +	continue_at(cl, bio_submit_split_done, NULL);
> +}

Firstly a small point:  Can bio_split ever return NULL here?  I don't
think it can, so there is no need to test.
But if it can, then calling generic_make_request(NULL) doesn't seem like a
good idea.

More significantly though::
  This is called from generic_make_request which can be called recursively and
enforces a tail-recursion semantic.
If that generic_make_request was a recursive call, then the
generic_make_request in __bio_submit_split will not start the request, but
will queue the bio for later handling.  If we then call bio_split again, we
could try to allocation from a mempool while we are holding one entry
allocated from that pool captive.  This can deadlock.

i.e. if the original bio is so large that it needs to be split into 3 pieces,
then we will try to allocate the second piece before the first piece has a
chance to be released.  If this happens in enough threads to exhaust the pool
(4 I think), it will deadlock.

I realise this sounds like a very unlikely case, but of course they happen.

One possible approach might be to count how many splits will be required,
then have an interface to mempools so you can allocate them all at once,
or block and wait.

Thanks,
NeilBrown


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