Re: [Linuxarm] [PATCH for next v1 0/2] gpio: few clean up patches to replace spin_lock_irqsave with spin_lock

[Andy Shevchenko <andy.shevchenko@gmail.com>]

On Wed, Feb 10, 2021 at 5:43 AM luojiaxing <luojiaxing@huawei.com> wrote:
> On 2021/2/9 17:42, Andy Shevchenko wrote:
> > On Tue, Feb 9, 2021 at 11:24 AM luojiaxing <luojiaxing@huawei.com> wrote:
> >> On 2021/2/8 21:28, Andy Shevchenko wrote:
> >>> On Mon, Feb 8, 2021 at 11:11 AM luojiaxing <luojiaxing@huawei.com> wrote:
> >>>> On 2021/2/8 16:56, Luo Jiaxing wrote:
> >>>>> There is no need to use API with _irqsave in hard IRQ handler, So replace
> >>>>> those with spin_lock.
> >>> How do you know that another CPU in the system can't serve the
> > The keyword here is: *another*.
>
> ooh, sorry, now I got your point.
>
> As to me, I don't think another CPU can serve the IRQ when one CPU
> runing hard IRQ handler,

Why is it so?
Each CPU can serve IRQs separately.

> except it's a per CPU interrupts.

I didn't get how it is related.

> The following is a simple call logic when IRQ come.
>
> elx_irq -> handle_arch_irq -> __handle_domain_irq -> desc->handle_irq ->
> handle_irq_event

What is `elx_irq()`? I haven't found any mention of this in the kernel
source tree.
But okay, it shouldn't prevent our discussion.

> Assume that two CPUs receive the same IRQ and enter the preceding
> process. Both of them will go to desc->handle_irq().

Ah, I'm talking about the same IRQ by number (like Linux IRQ number,
means from the same source), but with different sequence number (means
two consequent events).

> In handle_irq(), raw_spin_lock(&desc->lock) always be called first.
> Therefore, even if two CPUs are running handle_irq(),
>
> only one can get the spin lock. Assume that CPU A obtains the spin lock.
> Then CPU A will sets the status of irq_data to
>
> IRQD_IRQ_INPROGRESS in handle_irq_event() and releases the spin lock.
> Even though CPU B gets the spin lock later and
>
> continue to run handle_irq(), but the check of irq_may_run(desc) causes
> it to exit.
>
>
> so, I think we don't own the situation that two CPU server the hard IRQ
> handler at the same time.

Okay. Assuming your analysis is correct, have you considered the case
when all IRQ handlers are threaded? (There is a kernel command line
option to force this)

> >>> following interrupt from the hardware at the same time?
> >> Yes, I have some question before.
> >>
> >> There are some similar discussion here,  please take a look, Song baohua
> >> explained it more professionally.
> >>
> >> https://lore.kernel.org/lkml/e949a474a9284ac6951813bfc8b34945@hisilicon.com/
> >>
> >> Here are some excerpts from the discussion:
> >>
> >> I think the code disabling irq in hardIRQ is simply wrong.
> > Why?
>
>
> I mention the following call before.
>
> elx_irq -> handle_arch_irq -> __handle_domain_irq -> desc->handle_irq ->
> handle_irq_event
>
>
> __handle_domain_irq() will call irq_enter(), it ensures that the IRQ
> processing of the current CPU can not be preempted.
>
> So I think this is the reason why Song baohua said it's not need to
> disable IRQ in hardIRQ handler.
>
> >> Since this commit
> >> https://git.kernel.org/pub/scm/linux/kernel/git/torvalds/linux.git/commit/?id=e58aa3d2d0cc
> >> genirq: Run irq handlers with interrupts disabled
> >>
> >> interrupt handlers are definitely running in a irq-disabled context
> >> unless irq handlers enable them explicitly in the handler to permit
> >> other interrupts.
> > This doesn't explain any changes in the behaviour on SMP.
> > IRQ line can be disabled on a few stages:
> >   a) on the source (IP that generates an event)
> >   b) on IRQ router / controller
> >   c) on CPU side
>
> yes, you are right.
>
> > The commit above is discussing (rightfully!) the problem when all
> > interrupts are being served by a *single* core. Nobody prevents them
> > from being served by *different* cores simultaneously. Also, see [1].
> >
> > [1]: https://www.kernel.org/doc/htmldocs/kernel-locking/cheatsheet.html
>
> I check [1], quite useful description about locking, thanks. But you can
> see Table of locking Requirements
>
> Between IRQ handler A and IRQ handle A, it's no need for a SLIS.

Right, but it's not the case in the patches you provided.

--
With Best Regards,
Andy Shevchenko