From mboxrd@z Thu Jan  1 00:00:00 1970
From: martin f krafft <madduck@madduck.net>
Date: Sun, 26 Dec 2004 13:30:00 +0000
Subject: Re: how does udev rename an interface?
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also sprach Kay Sievers <kay.sievers@vrfy.org> [2004.12.26.1333 +0100]:
> Right, if something brings up the netif earlier, udev can't do
> anything.

Therefore, ifplugd should really not be called in hotplug.d, but
through net.agent, huh?

> On a successful rename, udev calls the /etc/dev.d/net/hotplug.dev
> script, which calls the /etc/hotplug.d/default/default.hotplug
> again with the corrected environment.

=46rom what I understand, udevsend is only one hook that is run, and
hotplug simply runs the next on competion. udevsend must therefore
somehow tell hotplug to abort the processing of remaining hooks
before invoking the /dev/dev.d script again. How does it do that?
With a non-zero exit code?

I am sorry for asking these questions... I am currently on an
ass-slow machine in my parents' house, and it would take me an hour
to figure this out... mutt takes 25 seconds to spawn. :/

> If /sbin/udevsend is used as the hotplug helper and udevd manages
> the complete hotplug event, only one correct hotplug netif call is
> visible to the hotplug scripts. The one for the old name will be
> "converted" to carry the new name and no second event needs to be
> faked.

Right, /etc/dev.d/net/hotplug.dev is the secret. It executes:

  exec /etc/hotplug.d/default/default.hotplug net

if the interface was renamed. If I can figure out how it stops the
hotplug instance that invoked udev from running further hooks, we
got a winner.

Cheers,

--=20
martin;              (greetings from the heart of the sun.)
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