Re: [SOLVED] RE: Weird environment for usb-storage script?

[Joerg Sommer <joerg@alea.gnuu.de>]

begin  "Michael Hale" <michaelh@cipheroptics.com> wrote:
>>From: linux-hotplug-devel-admin@lists.sourceforge.net 
>>[mailto:linux-hotplug-devel-admin@lists.sourceforge.net] On 
>>Behalf Of Michael Hale
>>Sent: Wednesday, September 17, 2003 1:37 PM
>>To: linux-hotplug-devel@lists.sourceforge.net
>>Subject: [SOLVED] RE: Weird environment for usb-storage script?
>>
>>I changed my usb-storage script to look like this:
>>#!/bin/sh
>>

add here: set -e to let the script die, if something returns with an
error.

>>exec >/tmp/foo.$$ 2>&1
>>set -x
>>invoke-rc.d ssh start
>>eject
>>
>>echo '#!/bin/sh
>>killall -9 sshd
>>eject -t' > $REMOVER
>>
>>chmod 777 $REMOVER
>>
>>...and it starts and stops the ssh server.  Now I just need to 
>>read some man pages and figure out what exec and set -x are 
>>actually doing :)

But it shouldn't look so. This is only for debuging. Take a look at
/tmp/foo.?? and you see what commands were executed and you see how they
are called.

> I am having trouble understanding what 'exec >/tmp/foo.$$ 2>&1' does.  I
> understand  that $$ becomes my pid and that stdout and stderr are
> redirected, but doesn't exec take a command?  What am I missing?  Also

exec removes normaly the process by another. If exec is called without a
command to execute, all that happens to the current process. All output
of the current process (produced by set -x) is written to /tmp/foo.??

> why would my commands not run previously if they generated output on
> stdout?

I don't know why. This is, why you should add debugging output.

Jörg.
end.
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