Re: Externalize SLIT table

Erich Focht
2004-11-05T17:13:24Z

Hi Jack,

the patch looks fine, of course.
> # cat ./node/node0/distance
> 10 20 64 42 42 22
Great!

But:
> # cat ./cpu/cpu8/distance
> 42 42 64 64 22 22 42 42 10 10 20 20
...

what exactly do you mean by cpu_to_cpu distance? In analogy with the
node distance I'd say it is the time (latency) for moving data from
the register of one CPU into the register of another CPU:
cpu*/distance : cpu -> memory -> cpu
node1 node? node2

On most architectures this means flushing a cacheline to memory on one
side and reading it on another side. What you actually implement is
the latency from memory (one node) to a particular cpu (on some
node).
memory -> cpu
node1 node2

That's only half of the story and actually misleading. I don't
think the complexity hiding is good in this place. Questions coming to
my mind are: Where is the memory? Is the SLIT matrix really symmetric
(cpu_to_cpu distance only makes sense for symmetric matrices)? I
remember talking to IBM people about hardware where the node distance
matrix was asymmetric.

Why do you want this distance anyway? libnuma offers you _node_ masks
for allocating memory from a particular node. And when you want to
arrange a complex MPI process structure you'll have to think about
latency for moving data from one processes buffer to the other
processes buffer. The buffers live on nodes, not on cpus.

Regards,
Erich